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3 years ago

How do I solve 1/2z=9 1/4?

Mathematics

1 answer:

Nastasia [14]3 years ago

6 0

Answer:

z = 9/2

Step-by-step explanation:

1/2z = 9 1/4?

z = 9/2

Explanation:

Simplify

9 x 1/4 → 9/4

Multiply 2 to both sides to cancel out the 2

1z = 9/4

Note: 1z is just z

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Step-by-step explanation:

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Write an inequality whose solutions are represented by the shaded part of the graph

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3 years ago

!30 POINTS! How can I use this trapezoid to prove the Pythagorean Theorem?

stiks02 [169]

Answer:

Pythagorean Theorem: c2 = a2 + b2

Find the area by adding the areas of the three triangles. The area of a right triangle is: A = ½bh

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3 years ago

A basic cellular phone plan costs $4 per month for 70 calling minutes. Additional time costs $0.10 per minute. The formula C= 4+

Harrizon [31]

Answer:

For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.

Step-by-step explanation:

The problem states that the monthly cost of a celular plan is modeled by the following function:

$C(x) = 4 + 0.10(x-70)$

In which C(x) is the monthly cost and x is the number of calling minutes.

How many calling minutes are needed for a monthly cost of at least $7?

This can be solved by the following inequality:

$C(x) \geq 7$

$4 + 0.10(x - 70) \geq 7$

$4 + 0.10x - 7 \geq 7$

$0.10x \geq 10$

$x \geq \frac{10}{0.1}$

$x \geq 100$

For a monthly cost of at least $7, you need to have at least 100 calling minutes.

How many calling minutes are needed for a monthly cost of at most 8:

$C(x) \leq 8$

$4 + 0.10(x - 70) \leq 8$

$4 + 0.10x - 7 \leq 8$

$0.10x \leq 11$

$x \leq \frac{11}{0.1}$

$x \leq 110$

For a monthly cost of at most $8, you need to have at most 110 calling minutes.

For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.

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3 years ago

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3 years ago