Question

at a school there are 10 students taking only chemistry, 9 students taking only physics 5 students taking both, and 16 students not taking either. if a student is randomly selected from the other school, what is the probability that they are taking chemistry or physics?

Answer 1

Answer:

If there are 10 students taking only chemistry, 9 students taking only physics, and 5 students only taking both chemisty and 16 students are taking neither; I would add 10+9+5+16=40 (total students) and divide 10/40 (25% chemistry) 9/40 (22.5% physics) 5/40 (12.5% both) 16/40 (40% neither)

Step-by-step explanation:

1. Determine a single event with a single outcome.

2. Identify the total number of outcomes that can occur.

3. Divide the number of events by the number of possible outcomes.

Answer 2

Answer:

3/5

Step-by-step explanation: