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skad [1K]
2 years ago
10

Tina is a waitress. On Monday she earned $4 per hour and $65 in tips. She made $93 total. Write and solve an equation to determi

ne how many hours she worked
Mathematics
1 answer:
Lera25 [3.4K]2 years ago
6 0
Let’s say hours = h

4h + 65 = 93
4x = 28
x = 7

7 hours!
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It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
hoa [83]

Answer:

Obese people

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, "almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ)".

Solution to the problem

Obese people

Let X the random variable that represent the minutes of a population (obese people), and for this case we know the distribution for X is given by:

X \sim N(373,67)  

Where \mu=373 and \sigma=67

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Let X the random variable that represent the minutes of a population (lean people), and for this case we know the distribution for X is given by:

X \sim N(526,107)  

Where \mu=526 and \sigma=107

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

The interval for the lean people is significantly higher than the interval for the obese people.

5 0
3 years ago
15w, when w = 12 I need help plz
Brrunno [24]

Answer:

180...

Step-by-step explanation:

15 x 12 = 180

6 0
3 years ago
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Which point is a solution to the system of equations graphed below?
UkoKoshka [18]
C.

This is because the x vale is clearly after the 6 and the y value is right on 5 
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For which values of x is the inequality 2(1 + x) > x + 8 true?
dlinn [17]

Answer:

the correct answer is D...

8 0
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What's the answer for these two?<br> y= -2x+9<br> y=4x-3
Klio2033 [76]

Answer:

4.5 and .75 or 9/2 and 3/4

4 0
3 years ago
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