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Julli [10]
1 year ago
14

9th Grade Geometry Describe and correct the error in finding the length of line segment AB

Mathematics
1 answer:
Nookie1986 [14]1 year ago
4 0

The correct option regarding the error in calculating the length of segment AB is given as follows:

There should have been a subtraction instead of an addition, and the correct length is of 3.5 units.

<h3>Where are points A and B?</h3>

Researching the problem on the internet, it is found that points A and B are on a number line, with coordinates given as follows:

  • A: 1.
  • B: 4.5.

<h3>What is the length of the segment?</h3>

The length of the segment is the absolute value of the subtraction of the endpoints, hence:

L = |4.5 - 1| = |1 - 4.5| = 3.5.

The error is that:

There should have been a subtraction instead of an addition, and the correct length is of 3.5 units.

More can be learned about the length of a segment at brainly.com/question/7694028

#SPJ1

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dangina [55]

Answer:

Step-by-step explanation:

That is correct.

P=4s=4(12)=48in

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2 years ago
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Write an equation perpendicular to x-4y=20 that passes through the point 2,-5
marshall27 [118]

Answer:

  4x +y = 3

Step-by-step explanation:

Perpendicular lines have slopes that are the negative reciprocals of one another. When the equation of the line is written in standard form like this, the equation of the perpendicular line can be written by swapping the x- and y-coefficients and negating one of them. Doing this much would give you ...

  4x +y = (constant)

Note that we have chosen to make the equation read 4x+y, not -4x-y. The reason is that "standard form" requires the leading coefficient to be positive.

Now, you just need to make sure the constant is appropriate for the point you want the line to go through. So, it needs to be ...

  4(2) +(-5) = constant = 3

The line of interest has equation ...

  4x + y = 3

3 0
3 years ago
A pencil costs $0.25 more than an eraser. If the cost of eight pencils is $6.80, what is the cost of one eraser?
Sever21 [200]
6.80/8 = 0.85 + 0.25= 1.10
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2 years ago
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Please help me with these ty!!!!
Digiron [165]
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3 years ago
Quadratics need help making parabola
timama [110]

Answer:

The equation of the parabola is y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4, whose real vertex is (x,y) = (2, -5.333), not (x,y) = (2, -5).

Step-by-step explanation:

A parabola is a second order polynomial. By Fundamental Theorem of Algebra we know that a second order polynomial can be formed when three distinct points are known. From statement we have the following information:

(x_{1}, y_{1}) = (-2, 0), (x_{2}, y_{2}) = (6, 0), (x_{3}, y_{3}) = (0, -4)

From definition of second order polynomial and the three points described above, we have the following system of linear equations:

4\cdot a -2\cdot b + c = 0 (1)

36\cdot a + 6\cdot b + c = 0 (2)

c = -4 (3)

The solution of this system is: a = \frac{1}{3}, b = - \frac{4}{3}, c = -4. Hence, the equation of the parabola is y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4. Lastly, we must check if (x,y) = (2, -5) belongs to the function. If we know that x = 2, then the value of y is:

y = \frac{1}{3}\cdot (2)^{2}-\frac{4}{3}\cdot (2) - 4

y = -5.333

(x,y) = (2, -5) does not belong to the function, the real point is (x,y) = (2, -5.333).

5 0
2 years ago
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