<u>Answer:</u>
Total Volume of composite figure = 635.2 cm³
<u>Steps:</u>
CV = h×3.14×(d/2)²
CV = 5×3.14(8/2)²
CV = 5×3.14(4)²
CV = 5×3.14×16
CV = 5×50.24
CV = 251.2 cm³
RV = h×w×l
RV = 4×8×12
RV = 4×96
RV = 384 cm³
TV = CV + RV
TV = 251.2 + 384
TV = 635.2 cm³
I'm assuming there is a graph with both functions plotted. The solution would be the point at which these two functions intersect. That coordinates of x and y for that point will yield the solutions for x and y that solve the system of equations.
<u>ANSWER</u>
A. (4,12)
<u>EXPLANATION</u>
The equations are:
and
To eliminate a variable we make the coefficients of that variable the same in both equations.
It is easier to eliminate x.
We multiply the first equation by 2 to get:
We add equations (2) and (3).
Divide both sides by 23
Put x=4 into equation (1).
The solution is (4,12)
5(a -2)
Djkajksnsj (gay panic because the answer he to be more the 20 characters)
Answer:
a) False
b) False
c) True
d) False
e) False
Step-by-step explanation:
a. A single vector by itself is linearly dependent. False
If v = 0 then the only scalar c such that cv = 0 is c = 0. Hence, 1vl is linearly independent. A set consisting of a single vector v is linearly dependent if and only if v = 0. Therefore, only a single zero vector is linearly dependent, while any set consisting of a single nonzero vector is linearly independent.
b. If H= Span{b1,....bp}, then {b1,...bp} is a basis for H. False
A sets forms a basis for vector space, only if it is linearly independent and spans the space. The fact that it is a spanning set alone is not sufficient enough to form a basis.
c. The columns of an invertible n × n matrix form a basis for Rⁿ. True
If a matrix is invertible, then its columns are linearly independent and every row has a pivot element. The columns, can therefore, form a basis for Rⁿ.
d. In some cases, the linear dependence relations among the columns of a matrix can be affected by certain elementary row operations on the matrix. False
Row operations can not affect linear dependence among the columns of a matrix.
e. A basis is a spanning set that is as large as possible. False
A basis is not a large spanning set. A basis is the smallest spanning set.
