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8_murik_8 [283]

2 years ago

6

Let x represent any year write an inequality in terms of x and 1822 that is true only for values of x that represent years befor

e the year that Brazil started its war for independence and

1 answer:

Kisachek [45]2 years ago

3 0

Answer: x<1822

I just did it.

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Given f(x) = 2x + 9, if f(x) = 15, find x.

AleksandrR [38]

Answer:

<h2>x = 3</h2>

Step-by-step explanation:

$f(x)=2x+9\\\\\text{Substitute}\ f(x)=15:\\\\15=2x+9\qquad\text{subtract 9 from both isdes}\\\\15-9=2x+9-9\\\\6=2x\qquad\text{divide both sides by 2}\\\\\dfrac{6}{2}=\dfrac{2x}{2}\\\\3=x\to x=3$

4 0

2 years ago

A local clothing shop is marking down all of its summer clothes by 75%. sarah would like to purchase a swimsuit that is original

trapecia [35]

a) $80 - ($80 x 0.75)

= $80 - $60

= $20

b) $20 x 0.10

= $2

c) $20 - $2

= $18

5 0

2 years ago

Write a rule for the nth term of the sequence. Then find a20. Assume the first termis a₁. 86, 79, 72, 65…

hodyreva [135]

Answer:

an = a(n-1) - 7

Step-by-step explanation:

the second term is smaller than the first term 7.

a20 = a19 - 7

a19 = a18 - 7

=> a20 = (a18 - 7) - 7

Then you can accumalate until a1

-> a20 = a1 - 19*7 = 86 - 19*7 = -47

5 0

2 years ago

2.5% of a population are infected with a certain disease. There is a test for the disease, however the test is not completely ac

Aleks04 [339]

Answer:

$P(disease/positivetest) = 0.36116$

Step-by-step explanation:

This is a conditional probability exercise.

Let's name the events :

I : ''A person is infected''

NI : ''A person is not infected''

PT : ''The test is positive''

NT : ''The test is negative''

The conditional probability equation is :

Given two events A and B :

P(A/B) = P(A ∩ B) / P(B)

$P(B) >0$

P(A/B) is the probability of the event A given that the event B happened

P(A ∩ B) is the probability of the event (A ∩ B)

(A ∩ B) is the event where A and B happened at the same time

In the exercise :

$P(I)=0.025$

$P(NI)= 1-P(I)=1-0.025=0.975\\P(NI)=0.975$

$P(PT/I)=0.904\\P(PT/NI)=0.041$

We are looking for P(I/PT) :

P(I/PT)=P(I∩ PT)/ P(PT)

$P(PT/I)=0.904$

P(PT/I)=P(PT∩ I)/P(I)

0.904=P(PT∩ I)/0.025

P(PT∩ I)=0.904 x 0.025

P(PT∩ I) = 0.0226

P(PT/NI)=0.041

P(PT/NI)=P(PT∩ NI)/P(NI)

0.041=P(PT∩ NI)/0.975

P(PT∩ NI) = 0.041 x 0.975

P(PT∩ NI) = 0.039975

P(PT) = P(PT∩ I)+P(PT∩ NI)

P(PT)= 0.0226 + 0.039975

P(PT) = 0.062575

P(I/PT) = P(PT∩I)/P(PT)

$P(I/PT)=\frac{0.0226}{0.062575} \\P(I/PT)=0.36116$

8 0

2 years ago

Segment MN has endpoints at M(-5, 4) and N(7, -5). What is the midpoint of MN???? PLZ HELP

Paha777 [63]

Theres a formula to find the midpoint it’s... (x1+x2)/2, (y1+y2)/2. You fill in the x’s and y’s to get (-5+7)/2 for x, which equals 1 and (4-5)/2 to get -0.5. (1, -0.5) is your answer

7 0

3 years ago