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klemol [59]
3 years ago
12

Factor the expression. X^2- 10xy + 24y?

Mathematics
1 answer:
lana66690 [7]3 years ago
7 0

Answer:

The expression is not factorable with rational numbers.  x^2-10xy + 24y

Step-by-step explanation:

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Is(0,-2) a solution of x+y=6
sergiy2304 [10]

Answer:

no

Step-by-step explanation:

x+y=6

Substitute the point into the equation and see if it is true

0 + -2 = 6

-2 =6

This is not true so the point is not a solution

4 0
3 years ago
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Use the drawing tools to form the correct answers on the graph. Plot the vertex and the axis of symmetry of this function: f(x)
CaHeK987 [17]

Answer:

Axis of Symmetry: x = 3

Vertex: (3, 5)

Step-by-step explanation:

Use a graphing calc.

6 0
4 years ago
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Equipment running at 100 per cent capacity sorts 13,000 packages each shift.
kolezko [41]

The machine will sort 11050 packages when it is operating at 85% capacity.

To solve this question, we have to find the rate at which the machine is operating at 85% capacity.

Data;

  • 13,000 at 100%
  • x at 85%

<h3>Rate</h3>

This is used to compare two values with respect to one another mostly under similar conditions.

13,000 = 100\\&#10;x = 85

cross multiply both sides and solve for x

x = \frac{13000*85}{100} \\&#10;x = 11050

The machine will sort 11050 packages when it is operating at 85%

Learn more on rates here;

brainly.com/question/14315509

5 0
2 years ago
Find the reduced row echelon form of the following matrices and then give the solution to the system that is represented by the
GaryK [48]

Answer:

a)

Reduced Row Echelon:

\left[\begin{array}{cccc}1&1/2&0&0\\0&1&7/4&0\\0&0&1&-4\end{array}\right]

Solution to the system:

x_3=-4\\x_2=-\frac{7}{4}x_3=7\\x_1=-\frac{1}{2}x_2=-\frac{7}{2}

b)

Reduced Row Echelon:

\left[\begin{array}{cccc}4&3&0&7\\0&0&2&-17\\0&0&2&-17\end{array}\right]

Solution to the system:  

x_3=-\frac{17}{2}\\x_1=\frac{7-3x_2}{4}

x_2 is a free variable, meaning that it has infinite possibilities and therefore the system has infinite number of solutions.

Step-by-step explanation:

To find the reduced row echelon form of the matrices, let's use the Gaussian-Jordan elimination process, which consists of taking the matrix and performing a series of row operations. For notation, R_i will be the transformed column, and r_i the unchanged one.

a) \left[\begin{array}{cccc}0&4&7&0\\2&1&0&0\\0&3&1&-4\end{array}\right]

Step by step operations:

1. Reorder the rows, interchange Row 1 with Row 2, then apply the next operations on the new rows:

R_1=\frac{1}{2}r_1\\R_2=\frac{1}{4}r_2

Resulting matrix:

\left[\begin{array}{cccc}1&1/2&0&0\\0&1&7/4&0\\0&3&1&-4\end{array}\right]

2. Set the first row to 1

R_3=-3r_2+r_3

Resulting matrix:

\left[\begin{array}{cccc}1&1/2&0&0\\0&1&7/4&0\\0&0&1&-4\end{array}\right]

3. Write the system of equations:

x_1+\frac{1}{2}x_2=0\\x_2+\frac{7}{4}x_3=0\\x_3=-4

Now you have the  reduced row echelon matrix and can solve the equations, bottom to top, x_1 is column 1, x_2 column 2 and x_3 column 3:

x_3=-4\\x_2=-\frac{7}{4}x_3=7\\x_1=-\frac{1}{2}x_2=-\frac{7}{2}

b)

\left[\begin{array}{cccc}4&3&0&7\\8&6&2&-3\\4&3&2&-10\end{array}\right]

1. R_2=-2r_1+r_2\\R_3=-r_1+r_3

Resulting matrix:

\left[\begin{array}{cccc}4&3&0&7\\0&0&2&-17\\0&0&2&-17\end{array}\right]

2. Write the system of equations:

4x_1+3x_2=7\\2x_3=-17

Now you have the reduced row echelon matrix and can solve the equations, bottom to top, x_1 is column 1, x_2 column 2 and x_3 column 3:

x_3=-\frac{17}{2}\\x_1=\frac{7-3x_2}{4}

x_2 is a free variable, meaning that it has infinite possibilities and therefore the system has infinite number of solutions.

7 0
3 years ago
If the probabilities that an automobile mechanic will service 3, 4, 5, 6, 7, or 8 or more cars on any given workday are, respect
Readme [11.4K]

Answer:

P(X\geq 5)=0.69

Step-by-step explanation:

We need to find the probability that the mechanic will service  or more cars.

It's a simpler one given that we have the probabilities of servicing 4 or less cars.

P(at least 5 cars) is given by subtracting the probabilities of servicing both 3 and 4 cars.

P(X\geq 5)=1-p(x=4)-p(x=3)\\P(X\geq5)=1-0.12-0.19\\P(X\geq5)=1-0.31\\=0.69

5 0
3 years ago
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