Find the mean, median, mode, and range of the data. 6,6,6,5,5,6,5,6,5. If necessary round to the nearest tenth
egoroff_w [7]
Answer:
ThE ANSWER IS: MEAN:5.6 MEDIAN: 6 MODE :6 RANGE: 1
Step-by-step explanation:
STEP BY STEP EXPLANATION
Answer:
The answer to your question is A = 441.50 km²
Step-by-step explanation:
Data
Big triangle Small triangle
base = 33 km base = 19 km
height = 40 km height = 23 km
Process
1.- Calculate the area of the big triangle
Area = base x height / 2
Substitution
Area = 33 x 40 / 2
= 1320 / 2
= 660 km²
2.- Calculate the area of the small triangle
Area = 19 x 23 / 2
= 437 / 2
= 218.5 km²
3.- Subtract the small area to the big area
Share area = 660 - 218.5
= 441.50 km²
5914 1404 393
Answer:
A) 1.3×10^37 ergs
B) 1.435×10^3 mm
Step-by-step explanation:
A) The amount of energy will be the product of the energy rate and time:
(3.9×10^33 ergs/s)×(3.25×10^3 s) =12.675×10^(33+3) ergs
= 1.2675×10^(1+36) ergs
= 1.2675×10^37 ergs ≈ 1.3×10^37 ergs
The mantissa of the result is the product 3.9×3.25, adjusted to have one digit left of the decimal point. The exponent of the result is the sum of the exponents of the factors, adjusted by 1 to match the adjustment in the mantissa.
The final value should be rounded to 2 significant figures, reflecting the precision of the sun's energy production.
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B) A millimeter is a small fraction of an inch. 10^-3 mm is a small fraction of the width of a human hair, so 1.435×10^-3 mm is not a reasonable estimate of the distance between railroad tracks.
On the other hand, 1.435×10^3 mm is 1.435 m, almost 56.5 inches. This is a much more reasonable measurement of the distance between railroad rails.
1.435×10^3 mm is more reasonable
Answer: 15
Explanation: Dividing the total amount of chocolate chips (3) by the amount per batch (0.2) will give you your answer of 15 batches...
87.3 for 3 58.2 for 2 hope it helps
