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yuradex [85]
2 years ago
5

A tree initially measured 38 1/2 feet tall. Over the next 5 1/2 years, it grew to a final height of 49 1/2 feet. During those 5

1/2 years, what was the average yearly growth rate of the height of the tree?
Mathematics
2 answers:
polet [3.4K]2 years ago
4 0

Answer:

2feets per year

Step-by-step explanation:

49,5-38,5=11feets --->this is how much it grew in 5,5years

11/5,5=2feets/year --->this is the yearly rate

nydimaria [60]2 years ago
3 0
I might be a little late but I’m pretty sure it’s 2ft every year
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The circumference of a circle is 60π cm. What is the radius of the circle
Sindrei [870]

Answer:

15 cm

Step-by-step explanation:

Circumference of circle= 2πr, where r us the radius of the circle.

Given that the circumference of circle is 60πcm,

60π= 2πr

Divide by 2 on both sides,

15π= πr

Divide by π on both sides,

15= r

Thus, radius of circle= 15cm.

8 0
3 years ago
The point A(-6, 8) has been transformed using the composition r(90,O) counterclockwise ∘Rx−axis . Where is A'?
Vikki [24]
A would now be a positive 6
7 0
3 years ago
Use quadratic regression to find
vovangra [49]

Answer:

y = 6x² -13x -5

Step-by-step explanation:

(1,-12) (2,-7) (5,80)

y = ax² + bx + c

-12 = a*1² + b*1 + c = a+b+c    (1)

-7 = 4a + 2b + c    (2)

80 = 25a + 5b + c   (3)

(2)-(1): 3a + b = 5    (4)

(3)-(2): 21a + 3b = 87   (5)

(4)*3:     9a + 3b = 15    (6)

(5)-(6):  12a = 72      a = 6

(4)                             b = -13

(2)                             c = -5

4 0
3 years ago
Determine the value of y, if x is -2.<br> y = x² +8
KiRa [710]

Answer:

y=x²+8

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6 0
2 years ago
3. At noon Lan is in his blue mini-van 300 km north of Makenna in her Bugatti. Lan heads south
LiRa [457]

Answer:

The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h

Step-by-step explanation:

At noon the location of Lan = 300 km north of Makenna

Lan's direction = South

Lan's speed = 60 km/h

Makenna's direction and speed = West at 75 km/h

The distance  Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km

The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km

The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km

Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.

By Pythagoras' theorem, we have;

s² = x² + y²

The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61

ds²/dt = dx²/dt + dy²/dt

2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt

2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900

ds/dt = 900/(2×30·√61) ≈ 1.92

The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h

5 0
3 years ago
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