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timama [110]
3 years ago
10

What is the value of y? y = ___

Mathematics
2 answers:
hjlf3 years ago
7 0

Answer:

Y=16.25

set it = 75

Hope that helps and feel free to ask me more questions :)Brainliest??



Step-by-step explanation:


marysya [2.9K]3 years ago
7 0
16.25 is the answer.hope it helps
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468 raffle tickets for 52<br> people<br><br> What’s the answer ?
kondaur [170]

Answer:

9

Step-by-step explanation:

you divide 468 by 52

468/52 = 9

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3 years ago
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Which function has a greater rate of change?
vitfil [10]
Dont you hate the people that give you the links just don’t listen to them
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Alejandro went out to eat dinner, and the meal cost $70.00. If Alejandro received a 24% discount, what was the total value of th
Tems11 [23]

Answer:

16.8

Step-by-step explanation:

7 0
3 years ago
What are the coefficients for the binomial expansion of (a + b)^3?
sashaice [31]

Answer:

Required coefficient :coefficient of 1st, 2nd, 3rd and 4th term are 1, 3,3,1 respectively.

Explanation:  

Formula for binomial expansion is (a+b)^n=^nC_0\cdot a^n\cdot b^0+^nC_1\cdota^(n-1)\cdot b^1+------b^n

We will substitute the values a=a, b=b and n=3  in the formula for binomial expansion we will get

^3C_0\cdot a^3\cdot b^0+^3C_1\cdot a^2\cdot b^1+^3C_2\cdot a^1\cdot b^2+^3C_3\cdot a^0\cdot b^3

After simplification of the terms we will get

a^3+3\cdot a^2\cdot b+3\cdot a\cdot b^2+b^3

Since, ^nC_r=\frac{n!}{(r!)(n-r)!}

Therefore the required coefficient : coefficients of 1st, 2nd, 3rd and 4th term are 1, 3,3,1 respectively.

5 0
3 years ago
Read 2 more answers
I tried to figure it out but i can't. i need to show the work and i don't know how to do it.​
Andreas93 [3]

Integration Formula:

\int\limits {x}^{n} \, dx =\frac{x^{n+1}}{n+1} + C

Integrate each term:

\int\ {x^{2}} \, dx = \frac{x^{3}}{3}

\int\ {x} \, dx =\frac{x^2}{2}

\int\ {5} \, dx = 5x

\int\ {x} \, dx =\frac{x^2}{2}

\int\ {2} \, dx = 2x

Altogether this becomes:

\frac{\frac{x^3}{3} - \frac{x^2}{2}-5x }{ \frac{x^2}{2}+2x}

Your limits are 1 and 2. Substitute both numbers into the equation and minus them from each other.

x = 2:

\frac{\frac{2^3}{3} - \frac{2^2}{2}-5(2) }{ \frac{2^2}{2}+2(2)}

-

x = 1:

[tex]\frac{\frac{1}{3} - \frac{1}{2}-5 }{ \frac{1}{2}+2}[/tex]

x = 2:

\frac{\frac{8}{3} - \frac{4}{2}-10 }{ \frac{4}{2}+4}

-

x = 1: \frac{\frac{8}{3} - 2-10 }{ 2+4}

=

-1.212317928

Now convert all the answers to integers and see which one matches -1.212317928:

Because it's a negative number, we know it can only be A or B.

(A) = -1.212317928

(B) = -1.19047619

The answer is A: -\frac{3}{2} +In\frac{4}{3}

<h2>(A) - 3/2 = ln 4/3</h2>

7 0
3 years ago
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