Tbh i depends on what kind of person you are. If you really like video games then go ahead but i guess what you are asking is how and that really doesnt answr your question but
1) YOU HAVE TO BE FULLY COMMITTED/ MOTIVATED TO THE GAME
that is the number 1 step.Also try to do a little research on the game and the systems, watch videos on how to take the system apart and back together.
I HAVE FAITH IN YOU!!! YOU CAN DO IT!!! TAKE CHARGE
Answer:
Bandwidth describes the maximum data transfer rate of a network or Internet connection. ... For example, a gigabit Ethernet connection has a bandwidth of 1,000 Mbps (125 megabytes per second). An Internet connection via cable modem may provide 25 Mbps of bandwidth.
Answer:
A logical unit of a system.
Explanation:
i'm thinking your are talking about system layers such as the ISO? Layers help identify the order of how the whole system works.
Answer:
a. facilitate improvements but do not necessarily cause them.
Explanation:
Decision Support Systems are interactive Information systems that assist decision makers in coming up with strategies that help the organisation achieve its goals .The model base of the DSS uses mathematical and statistical models to analyse information then it generates reports and suggest possible solutions that can be implemented .The system is capable of giving a specific solution and some even allow the decision makers to give input before suggesting the most applicable solution.The effectiveness of a DSS is equally as important as its efficiency .The DSS unlike the conventional decision-making process should be able to analyse information effectively and come up with solutions in the shortest possible time frame.
Answer:
See explaination for the program code
Explanation:
The code below
Pseudo-code:
//each item ai is used at most once
isSubsetSum(A[],n,t)//takes array of items of size n, and sum t
{
boolean subset[n+1][t+1];//creating a boolean mtraix
for i=1 to n+1
subset[i][1] = true; //initially setting all first column values as true
for i = 2 to t+1
subset[1][i] = false; //initialy setting all first row values as false
for i=2 to n
{
for j=2 to t
{
if(j<A[i-1])
subset[i][j] = subset[i-1][j];
if (j >= A[i-1])
subset[i][j] = subset[i-1][j] ||
subset[i - 1][j-set[i-1]];
}
}
//returns true if there is a subset with given sum t
//other wise returns false
return subset[n][t];
}
Recurrence relation:
T(n) =T(n-1)+ t//here t is runtime of inner loop, and innner loop will run n times
T(1)=1
solving recurrence:
T(n)=T(n-1)+t
T(n)=T(n-2)+t+t
T(n)=T(n-2)+2t
T(n)=T(n-3)+3t
,,
,
T(n)=T(n-n-1)+(n-1)t
T(n)=T(1)+(n-1)t
T(n)=1+(n-1)t = O(nt)
//so complexity is :O(nt)//where n is number of element, t is given sum
