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cestrela7 [59]
3 years ago
11

Convert the fraction to a decimal. Round to the nearest thousandths.135/650 Question 3 options: .2 .20 .2076923077 .208

Mathematics
1 answer:
Lilit [14]3 years ago
5 0
Turn in into a division problem :
135÷650=
About .208
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How to solve p^2-4p-32/p+4
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This expression can only be combined.

Add <span>p^2</span><span> and </span><span>−<span>32/p</span></span><span> to get </span><span><span><span>(<span>p^2</span>p−1⋅32)/</span>p</span>.
</span><span>−4p+<span><span><span>p^2 </span>p−1⋅32/</span>p</span>+4

</span>Multiply <span>−1</span><span> by </span>32<span> to get </span><span><span>−32</span>.
</span><span>−4p+<span><span><span>p^2 </span>p−32/</span>p</span>+4

</span>Find the common denominator<span>.
</span><span><span><span>−4pp/</span>p</span>+<span><span><span>p^2 </span>p−32/</span>p</span>+<span><span>4p/</span>p

</span></span>Combine<span> into one </span>fraction<span>.
</span><span><span>−4pp+<span>p^2 </span>p−32+4p/</span>p

</span>Simplify the numerator.
<span><span>−4<span>p^2</span>+<span>p^3</span>−32+4p/</span>p

</span>Simplify the expression<span>.
</span>
<span><span><span>p^3</span>−4<span>p^2</span>+4p−32/</span>p</span>
8 0
3 years ago
Read 2 more answers
Given m-2, m+4, 2m +1 are the first three terms of Arithmetic
ioda

Answer:

Given m-2, m+4, 2m +1 are the first three terms of Arithmetic

Step-by-step explanation:

Progression. Find the value of m and hence, list all the terms.​

5 0
3 years ago
Yuan needs to take a taxi to get to the movies. The taxi charges $3.50 for the first mile, and then $2.50 for each mile after th
NemiM [27]
It takes her 3 1/2 miles to get to the movies


3 0
4 years ago
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Jessica is baking a cake. The recipe says that she has to mix 96 grams of sugar into the flour. Jessica knows that 1 cup of this
Vikentia [17]
She should make more to reach the amount .
6 0
4 years ago
Suppose that prices of recently sold homes in one neighborhood have a mean of $225,000 with a standard deviation of $6700. Using
elena55 [62]

Answer:

211600 = 225000 -k*6700

k = \frac{225000-211600}{6700}= 2

238400 = 225000 +k*6700

k = \frac{238400-225000}{6700}= 2

So then the % expected would be:

1- \frac{1}{2^2}= 1- 0.25 =0.75

So then the answer would be 75%

Step-by-step explanation:

For this case we have the following info given:

\mu = 225000 represent the true mean

\sigma =6700 represent the true deviation

And for this case we want to find the minimum percentage of sold homes between $211,600 and $238,400.

From the chebysev theorem we know that we have 1 -\frac{1}{k^2} % of values within \mu \pm k\sigma if we use this formula and the limit given we have:

211600 = 225000 -k*6700

k = \frac{225000-211600}{6700}= 2

238400 = 225000 +k*6700

k = \frac{238400-225000}{6700}= 2

So then the % expected would be:

1- \frac{1}{2^2}= 1- 0.25 =0.75

So then the answer would be 75%

3 0
4 years ago
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