I like to start by dividing the given number by 2, unless a larger factor is evident.
1386 = 2(693). It's pretty obvious that we can divide 693 by 3: 693=3(231).
Then we have 1386 = (2)(3)(231). Try the same procedure. Does 231 have any integer, prime factors? See how far you can take this factoring.
Answer:
class boundaries are the end points of an open interval which contains the class interval such that the lower class boundary (LCB) is the LCL minus one-half the tolerance and the upper class boundary (UCB) is the UCL plus one -half the tolerance.
Answer:
It is 1 unit to the right of 0.
Step-by-step explanation:
First you have to take the whole number (43) and then take the decimal and put it over 100 (77/100).
