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3 years ago

2) Find the missing measure. Show your work. X = 130°

Mathematics

2 answers:

Marat540 [252]3 years ago

8 0

Answer:25

Step-by-step explanation:

alright so the triangle theorem states that all of the angles of a triangle add up to 180. we already of 130 so we take away 130 from 180 to get 50. If you see the two little lines on the triangles sides opposite of the two angles that we are missing then you can tell by those lines that the angles opposite of them are equal to each other. So you divide 2 from 50 to get 25 which is the value of x. Hope you understand this (:

Veronika [31]3 years ago

5 0

Answer:

The missing angle I believe is 25%.

Step-by-step explanation:

180-130=50

Divide 50 by 2 and it equals 25. 25 degrees for each angles.

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For each of the transactions in items 1 through 5, indicate the effects on the accounting equation elements.

oksian1 [2.3K]

Answer:

Decrease I think.

Sorry if it is wrong.

Hope it helped :)

6 0

2 years ago

Nick and Monica are paid $41.25 for their work. Nick worked 2.5 hours, and Monica worked 3 hours. They split the money according

vlada-n [284]

Answer:

BRIANLIEST PLZ

N = 18.75

M = 22.5

Step-by-step explanation:

Need the ratio of money paid to each. We know how the ratio of time is divided so we can use this ratio to find the amount paid.

T = t1 + t2 = 2.5 + 3 = 5.5

r1 =2.5/5.5

r2 = 3/5.5

Nick = r1 * 41.25 = 18.75

Monica = r2 * 41.25 = 22.5

7 0

3 years ago

How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?

BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

$\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}$

Where n = 8 and r = 0,1....8

When r = 0

$\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1$

When r = 1

$\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8$

When r = 2

$\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8$

When r = 3

$\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$

When r = 4

$\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70$

When r = 5

$\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$

When r = 6

$\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28$

When r = 7

$\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8$

When r = 8

$\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1$

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

3 0

3 years ago

18. What's 7?8 as a decimal? A. .78 B. 8.7 C. .875 D. 7.8

kenny6666 [7]

Each 1/8 is 0.125, so 7*0.125 in relation to 7/8 as a decimal is 0.875. Answer C.

3 0

3 years ago

Find in degrees. 11 B 6 [?]° Round to the nearest hundredth. Enter

avanturin [10]

Answer:

$\beta = 28.610$

Step-by-step explanation:

in this case we have a right angled triangle, whenever you see this triangle think of the TRIG RATIOS * sin, cos & tan* but if it was another triangle besides right angled triangle you use SINE RULE OR COSINE RULE

SOLUTION

$\tan( \beta ) = \frac{opposite}{adjecent} \\ \tan( \beta ) = \frac{6}{11} \\ \beta = tan(inverse)( \frac{6}{11} ) \\ \beta = 28.61045$

5 0

1 year ago