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Artist 52 [7]
3 years ago
14

Puter Science (IS)

Computers and Technology
1 answer:
Tamiku [17]3 years ago
3 0

Answer: Campus Area Network

Explanation: Got it right on Edge.

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Bluetooth 5 allows data to be transferred between two devices at a rate of
Minchanka [31]

Answer:

2 MBPS.

Explanation:

The Bluetooth 5 raises the data transmission of information throughput from 1 Mbps to the 2 Mbps. The main advantage of Bluetooth 5 do not increasing the energy  utilization.The Bluetooth 5 increasing the volume of information that technologies can be distribute.

  • The main advantage of Bluetooth 5 decreases the time it would take to send and receive the signals,
  • The previous version of Bluetooth transmit the information from one device to the another with the 1 Mbps speed  .
7 0
4 years ago
Which of these files, when included in a program, will provide user assistance?
34kurt

Answer:

Answer for this question is D

Explanation:

Help flies

4 0
3 years ago
Read 2 more answers
Write a recursive method to return the number of uppercase letters in a String. You need to define the following two methods. Th
satela [25.4K]

Answer:

<u>Recursive function with two parameters that return the number of uppercase letters in a String</u>

public static int count(String str,int h)//Defining function

{

      if(str.charAt(0)>='A' && str.charAt(0)<='Z')//Checking the characters from A to Z

{

          h++; //incrementing the counter

          if(str.length()>=2){

              return count(str.substring(1),h);//recalling function

          }

      }

      if(str.length()>=2){

              return count(str.substring(1),h); //recalling function

      }

      return h;

  }

This is the recursive function with the name count of return type integer,having parameters str of string type and h of integer type.In this we are checking the characters at a particular position from A to Z.

<u>Recursive function with one parameter that return the number of uppercase letters in a String</u>

public static int count(String str)//Defining function

{

      if(str.charAt(0)>='A' && str.charAt(0)<='Z')//Checking the characters from A to Z

{

          count++; //incrementing the counter

          if(str.length()>=2){

              return count(str.substring(1));//recalling function

          }

      }

      if(str.length()>=2){

              return count(str.substring(1)); //recalling function

      }

      return count;

  }

This is the recursive function with the name count of return type integer,having parameters str of string type .In this we are checking the characters at a particular position from A to Z.

<u>Java program that return the number of uppercase letters in a String</u>

import java.util.*;

public class Myjava{

static int count =0;//Defining globally  

 

public static int count(String str,int h)//Defining function

{

      if(str.charAt(0)>='A' && str.charAt(0)<='Z')//Checking the characters from A to Z

{

          h++;

//incrementing the counter

          if(str.length()>=2){

              return count(str.substring(1),h);//recalling function

          }

      }

      if(str.length()>=2){

              return count(str.substring(1),h);

//recalling function

      }

      return h;

 

  }

  public static void main(String[] args)//driver function

  {

      System.out.println("Enter a string");//taking input

      Scanner scan = new Scanner(System.in);

      String s = scan.nextLine();

      int h =0;

      System.out.println("Counting the Uppercase letters: "+count(s,h));

  }

}

<u>Output</u>

Enter a string  WolFIE

Counting the Uppercase letters: 4

4 0
3 years ago
write two paragraphs (at least 5 sentences each) about what President Biden and Vice-President Harris plan to do during the firs
frozen [14]

Answer:

writing one in comments bec i don't have time for both sorry

4 0
3 years ago
Write a loop that reads positive integers from console input, printing out those values that are even, separating them with spac
zvonat [6]

Hello, since you did not specify a programming language, I wrote this algorithm in C++. Good luck!

<h2>Code:</h2>

#include <iostream>

#include <vector>

std::vector<int> v;

int main(int argc, char* argv[]) {

   while(1) {

   int temp;

   std::cout << "\nEnter a number: ";std::cin>>temp;

   

   if(temp<0) {

       std::cout << "\nEven number(s) is/are:\n---------------------\n";

       for(int i=0;i<v.size();i++) {

           if(v.at(i)%2==0) std::cout << v[i] << " ";

           else continue;

       }

       std::cout << std::endl;

       break;

   }else {

       v.push_back(temp);

   }

}

   return 0;

}

4 0
2 years ago
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