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juin [17]
3 years ago
5

The gas tank of a riding mower holds 5 liters of gas how many 5 liter gas tanks can you fill from a full 20 liter gas tank

Mathematics
2 answers:
Lisa [10]3 years ago
7 0
4 liters 4 times 5 = 20
Dima020 [189]3 years ago
3 0
You can fill up 4 tanks because 20 divided by 5 is 4
You might be interested in
What is this pls help me 1/3 times 3/7
alex41 [277]

Answer:

2/21

Step-by-step explanation:

2/21 is the answer...........that is the fraction......

x+1/3=3/7

x=3/7-1/3

LCM=21

x=9/21-7/21

x=2/21

7 0
3 years ago
Evelyn took a job that paid $100 the first week. She was guaranteed a raise of 2% each week. How much money will she make in all
Zanzabum
This is a growth exponential equation. 
It can be solved 2 ways, but one of them is long and cumbersome and not worth the effort. You could take 2% of the base number and keep doing it 8 times. 

The other way is to realize that 100$ + 2% of 100 dollars can be written as 2% = 2/100 = 0.02 and that can be written as
100( 1 + 0.02 ) = 100(1.02) Now if you want this to be raised 8 times, it will look like this
y = 100(1.02)^(n - 1) for any number of weeks
y(8) = 100(1.02)^7 = 114.87
So at week 1 she has 100 dollars and at week 8 she has 114.87 dollars.

Comment
Realize that if her boss does not want to give her compounded interest that she could still make
Ln = L_{8} = 100 + (n - 1)*0.02*100
L_{8} = 100 + 7*0.02*100 = 100 + 14. = 114
By compounding she makes a whole 0.87$ more. 


6 0
2 years ago
Calculate the sample mean and sample variance for the following frequency distribution of heart rates for a sample of American a
spin [16.1K]

Answer:

Mean = 68.9

s^2 =18.1 --- Variance

Step-by-step explanation:

Given

\begin{array}{cccccc}{Class} & {51-58} & {59-66} & {67-74} & {75-82} & {83-90} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}

Solving (a): Calculate the mean.

The given data is a grouped data. So, first we calculate the class midpoint (x)

For 51 - 58.

x = \frac{1}{2}(51+58) = \frac{1}{2}(109) = 54.5

For 59 - 66

x = \frac{1}{2}(59+66) = \frac{1}{2}(125) = 62.5

For 67 - 74

x = \frac{1}{2}(67+74) = \frac{1}{2}(141) = 70.5

For 75 - 82

x = \frac{1}{2}(75+82) = \frac{1}{2}(157) = 78.5

For 83 - 90

x = \frac{1}{2}(83+90) = \frac{1}{2}(173) = 86.5

So, the table becomes:

\begin{array}{cccccc}{x} & {54.5} & {62.5} & {70.5} & {78.5} & {86.5} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}

The mean is then calculated as:

Mean = \frac{\sum fx}{\sum f}

Mean = \frac{54.5*4+62.5*3+70.5*11+78.5*13+86.5*4}{6+3+11+13+4}

Mean = \frac{2547.5}{37}

Mean = 68.9 -- approximated

Solving (b): The sample variance:

This is calculated as:

s^2 =\frac{\sum (x - \overline x)^2}{\sum f - 1}

So, we have:

s^2 =\frac{(54.5-68.9)^2+(62.5-68.9)^2+(70.5-68.9)^2+(78.5-68.9)^2+(86.5-68.9)^2}{37 - 1}

s^2 =\frac{652.8}{36}

s^2 =18.1 -- approximated

5 0
2 years ago
Identify the coefficient in the term 7 x2y3 .
Ivanshal [37]

7 x^2y^3

The coefficient is 7

7 0
3 years ago
Which rigid transformation would map ΔAQR to ΔAKP?
Virty [35]
Rotation around point a

8 0
3 years ago
Read 2 more answers
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