Answer:
36
Step-by-step explanation:
You subtract 180 from 56 then add your answer, 124 to 20, then subtract 144 from 180 to get 36
Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :

B )
Acceleration a is given by :

Hence , this is the required solution .
Answer:
1 bag of 64
2 bags of 32
4 bags of 16
Or 8 bags of 8
Step-by-step explanation:
that's the answer I think for however your answer is there were no answers to pick from....
add up the X values and y values and divide by two
X=(-2+6)/2=2
Y=(-4=8)/2=2
Step-by-step explanation:
You're asking why

let's transpose the first equation for y
-2x-6y=18
-6y=18+2x
6y=-18-2x
y=-18/6-2x/6
y=-3-⅓x as required