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DiKsa [7]
3 years ago
11

The perimeter of a rectangle is 48 feet. If the length measures 16 feet, which is the width?

Mathematics
1 answer:
bekas [8.4K]3 years ago
6 0

Answer:

B. 8ft

Step-by-step explanation:

The perimeter of a rectangle is given by

P = 2(l+w) where l is the length and w is the width

Substituting in the given values

48 = 2(16+w)

Divide each side by 2

48/2 = 2/2(16+w)

24 = 16+w

Subtract 16 from each side

24-16 =16+w-16

8 =w

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Help plz:))) I’ll mark u brainliest
Rama09 [41]

Answer: 92

Step-by-step explanation: diagonally across would also be 88 so 88+88 is 176 and the total needs to be 360 so 360-176=184 so 184 divided by 2 is 92 which is your answer

4 0
3 years ago
Question 2 (1 point)
Montano1993 [528]

Answer:

The correct option is;

C. She should go back and remeasure all of her specimens again to find the error. If she can't do this, she should eliminate the outlier from the analysis, because this is an error in recording

Step-by-step explanation:

In order to minimize error in measurement, some valuable steps includes;

1) Perform a double check on all measurements to ensure that the measurements recorded are accurate

2) Ensure proper training before taking measurements

3) Measurements should only be taken under controlled conditions

4) Separate the entire population into smaller groups for proper recording

5) Have a second observer double check the records

3 0
3 years ago
Write a polynomial that represents the length of the rectangle<br><br> help please !!
disa [49]

Answer:

\textsf{Length}=0.8x^2-0.7x+0.7\quad \sf units

Step-by-step explanation:

Area of a rectangle = width × length

Therefore, to find the length of the rectangle, we need to divide the area by the width.

Using long division:

\large\begin{array}{r}0.8x^2-0.7x+0.7\phantom{)} \\x+0.5{\overline{\smash{\big)}\,0.8x^3-0.3x^2+0.35x+0.35\phantom{)}}}\\-~\phantom{(}\underline{(0.8x^3+0.4x^2)\phantom{-b))))))))))))))}}\\0-0.7x^2+0.35x+0.35\phantom{)}\\ \underline{-~\phantom{()}(-0.7x^2-0.35x)\phantom{-b)))))}}\\ 0.7x+0.35\phantom{)}\\\underline{-~\phantom{()}(0.7x-0.35)}\\ 0\phantom{)}\end{array}

Therefore, the <u>length</u> of the rectangle is:

0.8x^2-0.7x+0.7

5 0
2 years ago
HELPPPP PLEASEEEEEEE
Bezzdna [24]
30043——————3.0043 x 10^4
30.043—————— 3.0043 x10^1
0.0030043—————-3.0043 x 10^-3
0.30043—————-3.0043 x 10^-1
3.0043————-3.0043 x 10^0

Hope this helps please mark brainiest
8 0
3 years ago
I need help please help me
oksian1 [2.3K]

Answer:

d=2

Step-by-step explanation:

6 0
3 years ago
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