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mamaluj [8]
3 years ago
7

Why does radius increase as you go down a group (hint: think Bohr-Rutherford diagrams)? Why would an increase in radius make it

easier to lose an outer electron (i.e. give a lower ionization energy)?
Chemistry
1 answer:
harina [27]3 years ago
4 0

Answer:

i rlly dont know i just want pionts pls follow me btw

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Answer: _{38}^{90}\textrm{Sr}\rightarrow _{36}^{86}\textrm{Kr}+_2^4\textrm{He}

Explanation:

Alpha Decay: In this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. The mass number is reduced by 4 units and atomic number is reduced by 2 units.

General representation of an element is given as:   _Z^A\textrm{X}

where,

Z represents Atomic number

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X represents the symbol of an element

General representation of alpha decay :

_Z^A\textrm{Sr}\rightarrow _{Z-2}^{A-4}Y+_2^4\alpha

The  balanced nuclear equation when the isotope Strontium-90 decays by Q-  decay is :

_{38}^{90}\textrm{Sr}\rightarrow _{36}^{86}\textrm{Kr}+_2^4\textrm{He}

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