Why does radius increase as you go down a group (hint: think Bohr-Rutherford diagrams)? Why would an increase in radius make it
easier to lose an outer electron (i.e. give a lower ionization energy)?
1 answer:
Answer:
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pretty sure its B thank me later
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the answer is 0.015
Answer:
The answer to your question is: CH₄ + 3/2 O₂ ⇒ CO₂ + 2 H₂O
Explanation:
Methane = CH₄
Oxygen = O
Carbon dioxide = CO₂
Water = H₂O
CH₄ + 3/2 O₂ ⇒ CO₂ + 2 H₂O
This is the balanced equation