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Gnoma [55]
3 years ago
14

• describe/recognize the molecular structure of water. • define these terms o matter o element o atom • know and be able to defi

ne the subatomic particles found in atoms. • define atomic number and atomic mass. • be able to determine the reactivity of an element by how many electrons are in the valence shell. • distinguish between ionic, covalent, polar covalent, nonpolar covalent and hydrogen bonds. • state the difference between a compound and a molecule.
Chemistry
1 answer:
artcher [175]3 years ago
4 0
Good luck buddy hhjjjjjjj
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Arrange these elements based on their atomic radii. ga, f, s, as
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please have look at Periodic table , you will solve it yourself !

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The unbalanced equation below shows the combustion of methane.
Ratling [72]
B. 1, 2, 1, 2. You balance the equation by making sure there are equal elements on both sides.
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3 years ago
A household cleaner has a pH around 10. It would be considered
anyanavicka [17]

Answer:

an acid

Explanation:

A household cleaner has a pH around 10. It would be considered. a base. an acid. neutral. a liquid.

4 0
3 years ago
Read 2 more answers
The literature value for the Ksp of Ca(OH)2 at 25 °C is 4.68E−6. Imagine you ran the experiment and got a calculated value for K
svet-max [94.6K]

Answer:

D. The Ca[OH]2 solution may have been unsaturated

Explanation:

The solubility product constant Ksp of any given chemical compound is a term used to describe the equilibrium between a solid and the ions it contains solution. The value of the Ksp indicates the extent to which any compound can dissociate into ions in water. A higher the Ksp, implies more greater solubility of the compound in water.

If the Ksp is more than the value in literature, this false value must have arisen from the fact that the solution was unsaturated hence it appears to be more soluble than it should normally be when saturated.

8 0
4 years ago
Given the following UNBALANCED reaction: NH3 (g) <--> N2 (g) + H2 (g) If 1
Yakvenalex [24]

Answer:

C. 1.35

Explanation:

                                                     2NH3 (g) <-->          N2 (g) +             3H2 (g)

Initial concentration                2.2 mol/0.95L       1.1 mol/0.95L           0

change in concentration        2x                             x                           3x

                                                 -0.84 M                  +0.42M                +1.26M

Equilibrium                       1.4 mol/0.95L=1.47M        1.58 M                   1.26 M

concentration

Change in concentration(NH3) = (2.2-1.4)mol/0.95 L = 0.84M

Equilibrium concentration (N2) = 1.1/0.95 +0.42=1.58 M

Equilibrium concentration(NH3) = 1.4/0.95 = 1.47M

K = [N2]*{H2]/[NH3] = 1.58M*1.26M/1.47M = 1.35 M

8 0
3 years ago
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