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Gnoma [55]
3 years ago
14

• describe/recognize the molecular structure of water. • define these terms o matter o element o atom • know and be able to defi

ne the subatomic particles found in atoms. • define atomic number and atomic mass. • be able to determine the reactivity of an element by how many electrons are in the valence shell. • distinguish between ionic, covalent, polar covalent, nonpolar covalent and hydrogen bonds. • state the difference between a compound and a molecule.
Chemistry
1 answer:
artcher [175]3 years ago
4 0
Good luck buddy hhjjjjjjj
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Which variable is held constant when testing for the thermal expansion relationship of a gas?
Alenkasestr [34]

pressure is the correct answer

7 0
3 years ago
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The enthalpy of solution (∆H) of KOH is -57.6 kJ/mol. If 3.66 g KOH is dissolved in enough water to make a 150.0 mL solution, wh
Wewaii [24]

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

The enthalpy of solution of KOH is -57.6 kJ/mol. We can calculate the heat released by the solution (Qr) of 3.66 g of KOH considering that the molar mass of KOH is 56.11 g/mol.

3.66g \times \frac{1mol}{56.11g} \times \frac{(-57.6kJ)}{mol} = -3.76 kJ

According to the law of conservation of energy, the sum of the heat released by the solution of KOH (Qr) and the heat absorbed by the solution (Qa) is zero.

Qr+Qa = 0\\\\Qa = -Qr = 3.76 kJ

150.0 mL of solution with a density of 1.02 g/mL were prepared. The mass (m) of the solution is:

150.0 mL \times \frac{1.02g}{mL}  = 153 g

Given the specific heat capacity of the solution (c) is 4.184 J/g・°C, we can calculate the change in the temperature (ΔT) of the solution using the following expression.

Qa = c \times m \times \Delta T\\\\\Delta T = \frac{Qa}{c \times m} = \frac{3.76 \times 10^{3}J  }{\frac{4.184J}{g.\° C }  \times 153g} = 5.87 \° C

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

Learn more: brainly.com/question/4400908

7 0
2 years ago
How are changes between phases consistent with the law of conservation of matter
Arada [10]
<span>I'm assuming its cause the total mass is the same, changes between phases are physical... solid ice and liquid water have the same mass</span>
8 0
3 years ago
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If you pump 40.088g of octane (C8H18) into your gas tank, how mant molecules of octane are you pumping
Sonbull [250]

Answer:

2.11 × 10²³ molecules of octane

Explanation:

Given data:

Mass of octane = 40.088 g

Molecules of octane = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

Number of moles of octane:

Number of moles = mass/ molar mass

Number of moles = 40.088 g / 114.23 g/mol

Number of moles =  0.351 mol

Number of molecules:

one mole of octane = 6.022 × 10²³ molecules of octane

0.351 mole of octane = 0.351 ×  6.022 × 10²³ molecules of octane

2.11 × 10²³ molecules of octane

6 0
3 years ago
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Evaluate the nature of the thermal vibrations in each of the four states of matter
Sidana [21]

Answer:

its matter

Explanation:

i just did the test

7 0
2 years ago
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