Answer:
1/4
Step-by-step explanation:
3 out of 12 stored over 10:
3 / 12
simplify
1/4
Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m
time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s
the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s
Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.
Answer: ok we will help
Step-by-step explanation:
he need our help
Answer:
1.35 miles is the distance walked in decimal form
Step-by-step explanation:
1 (decimal) 35
Answer:
The answer is the third option from the top:
0, 0, 11, 15, 26, 32, 45, 46, 46, 46, 60, 71, 84, 88
