An interactive poll on the front page of the CNN website in October 2011 asked if readers would consider voting for Herman Cain,
1 answer:
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Answer:
The coordinates of are
and
.
Step-by-step explanation:
Let be and
endpoints of segment AB and
a point located 7/10 the way from A to B. Vectorially, we get this formula:
By Linear Algebra we get the location of :
If we know that and
, then:
The coordinates of are
and
.
Answer:
If we compare the p value and the significance level given we see that
so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.
The best option for this case would be:
We would switch to α = .01 for a more powerful test.
Step-by-step explanation:
Previous concepts and data given
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
represent the sample mean
represent the sample standard deviation
n=18 represent the sample selected
significance level
State the null and alternative hypotheses.
We need to conduct a hypothesis in order to check if the mean is less than 40, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:
(1)
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
Calculate the statistic
We can replace in formula (1) the info given like this:
P-value
First we need to calculate the degrees of freedom given by:
Since is a left tailed test the p value would be:
Conclusion
If we compare the p value and the significance level given we see that
so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.
The best option for this case would be:
We would switch to α = .01 for a more powerful test.
Since the p values is just a little higher than th significance level 0.051>0.05 but the values are two close. If we change the value of the significance by 0.01, we have that 0.051>0.01 and it's a more powerful test.
Each quarter of a set of data is denoted by a quartile:
The 25th percentile makes up the first quartile Q1.
The 50th percentile represents the second quartile Q2.
The 75th percentile is the third quartile, or Q3.
Finding the second quartile, Q2, is simple. It divides an ordered data set into upper and lower half and is the median of any data set.
The median of the bottom half, excluding the value of Q2, makes up the first quartile, or Q1. The median of the upper half, excluding the value of Q2, makes up the third quartile, or Q3.
Sort the values in your data set from lowest to highest.
the median, please. Q2 stands for the second quartile.
Divide the ordered data collection in half at Q2.
The median of the lower half of the data makes up the lower quartile Q1.
The median of the data's upper half represents the upper quartile Q3.
When determining the first and third quartiles, omit the median if the size of the data set is unusual.
The median, if the size of the data collection is even, is the average of the middle two values. Add the two figures together, then divide by two. The value of the median, which divides the data set into lower and higher half, is
How to Find Interquartile Range
The interquartile range IQR is the range in values from the first quartile Q1 to the third quartile Q3. Find the IQR by subtracting Q1 from Q3.
IQR = Q3 - Q1
How to Find the Minimum
The minimum is the smallest value in a sample data set. Ordering a data set from lowest to highest value, x1 ≤ x2 ≤ x3 ≤ ... ≤ xn, the minimum is the smallest value x1. The formula for minimum is:
Min=1=min()=1
How to Find the Maximum
The maximum is the largest value in a sample data set.
Ordering a data set from lowest to highest value, x1 ≤ x2 ≤ x3 ≤ ... ≤ xn, the maximum is the largest value xn. The formula for maximum is:
Max==max()=1
How to Find the Range of a Set of Data
The range of a data set is the difference between the minimum and maximum. To find the range, calculate xn minus x1.
=−1
So to Answer your question
The 25th percentile makes up the first quartile Q1.
The 50th percentile represents the second quartile Q2.
The 75th percentile is the third quartile, or Q3.
Finding the second quartile, Q2, is simple. It divides an ordered data set into upper and lower half and is the median of any data set.
The median of the bottom half, excluding the value of Q2, makes up the first quartile, or Q1. The median of the upper half, excluding the value of Q2, makes up the third quartile, or Q3.
Sort the values in your data set from lowest to highest.
the median, please. Q2 stands for the second quartile.
Divide the ordered data collection in half at Q2.
The median of the lower half of the data makes up the lower quartile Q1.
The median of the data's upper half represents the upper quartile Q3.
When determining the first and third quartiles, omit the median if the size of the data set is unusual.
The median, if the size of the data collection is even, is the average of the middle two values. Add the two figures together, then divide by two. The value of the median, which divides the data set into lower and higher half, is
How to Find Interquartile Range
The interquartile range IQR is the range in values from the first quartile Q1 to the third quartile Q3. Find the IQR by subtracting Q1 from Q3.
IQR = Q3 - Q1
How to Find the Minimum
The minimum is the smallest value in a sample data set. Ordering a data set from lowest to highest value, x1 ≤ x2 ≤ x3 ≤ ... ≤ xn, the minimum is the smallest value x1. The formula for minimum is:
Min=1=min()=1
How to Find the Maximum
The maximum is the largest value in a sample data set.
Ordering a data set from lowest to highest value, x1 ≤ x2 ≤ x3 ≤ ... ≤ xn, the maximum is the largest value xn. The formula for maximum is:
Max==max()=1
How to Find the Range of a Set of Data
The range of a data set is the difference between the minimum and maximum. To find the range, calculate xn minus x1.
=−1
So to Answer your question