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3 years ago

10

Geoff planted dahlias in his garden. Dahlias have bulbs that divide

1 answer:

Tcecarenko [31]3 years ago

7 0

Answer:

Geoff planted dahlias in his garden. Dahlias have bulbs that divide and reproduce underground. In the first year, Geoff's garden produced 4 bulbs. In the second year, it produced 8 bulbs, and in the third year, it produced 16 bulbs

Step-by-step explanation:

You might be interested in

The nth term of a sequence is -3-3n what is the 6th term

Serga [27]

Answer:

-21

Step-by-step explanation:

if for s(n) = -3-3n

then s(6) = -3-3*6 = -3-18 = -21

8 0

3 years ago

My favorite songstress gives away 25% of the sales of her signature fragrance collection to her charity. Last month her sales we

guajiro [1.7K]

Answer:

300

Step-by-step explanation:

4=25%

12=1200

12/4=3

add the zeroes from 1200

300

to make sure...

300x4=1200

5 0

3 years ago

The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature

Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

$T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$

Where

$(t) = \ time$

$T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)$

$T_{s} = Surrounding \ temperature$

$T_{0} = Initial \ temperature \ of \ the \ body$

$k = constant$

From the question,

$T_{0} = 86 ^{o}C$

$T_{s} = -20 ^{o}C$

∴ $T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C$

$T_{0} - T_{s} = 106^{o} C$

Therefore, the equation $T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$ becomes

$T_{(t)}=-20+106 e^{kt}$

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time $t = 1 \ hour$ , $T_{(t)} = 58^{o}C$

Then, we can write that

$T_{(1)}=58 = -20+106 e^{k(1)}$

Then, we get

$58 = -20+106 e^{k(1)}$

Now, solve for $k$

First collect like terms

$58 +20 = 106 e^{k}$

$78 =106 e^{k}$

Then,

$e^{k} = \frac{78}{106}$

$e^{k} = 0.735849$

Now, take the natural log of both sides

$ln(e^{k}) =ln( 0.735849)$

$k = -0.30673$

This is the value of the constant $k$

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at $t = 2 \ hours$

From

$T_{(t)}=-20+106 e^{kt}$

Then

$T_{(2)}=-20+106 e^{(-0.30673 \times 2)}$

$T_{(2)}=-20+106 e^{-0.61346}$

$T_{(2)}=-20+106\times 0.5414741237$

$T_{(2)}=-20+57.396257$

$T_{(2)}=37.396257 \ ^{o}C$

$T_{(2)} \approxeq 37.40 \ ^{o}C$

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

6 0

2 years ago

Read 2 more answers

a guy is washing 32 feet off the ground. he positions the ladder at an angle of 67° with the ground. how tall is the ladder

irina [24]

Answer:

34.76 feet

Step-by-step explanation:

trig

SOH CAH TOA

6 0

3 years ago

Which digit is in the hundredths place?<br><br> 18.36<br><br> 8<br> 3<br> 1<br> 6

Karolina [17]

Answer:

6.becuase after the decimal or "." it goes 00.tenth, hundredth, thousandth, and so on

Step-by-step explanation:

PLEASE GIVE BRAINLIEST OR 5 ⭐

4 0

2 years ago

Read 2 more answers