jane works 40 hours per week. due to illness , jane worked 3/5 of her scheduled hours. how many hours did jane work last week?
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Answer:
a. We fail reject to the null hypothesis because zo = -5.84 < 1.65 = zα and P-value = 1 (approximately)
b. The confidence Interval for u1 - u2 is; 6.79 ≤ u1 - u2
c. The power of the test = 1 -
β = 0.998736
d. The sample size is adequate because the power of the test is approximately 1
Step-by-step explanation:
Given
Standard Deviations; σ1 = σ2 = 1.0 psi
Size: n1 = 10; n2 = 12
X = 162.5; Y = 155.0
Let X1, X2....Xn be a random sample from Population 1
Let Y1, Y2....Yn be a random sample from Population 2
We assume that both population are normal and the two are independent.
Therefore, the test statistic
Z = (X - Y - (u1 - u2))/√(σ1²/n1 + σ2²/n2)
See attachment for explanation
The equation of the line that contains (−6, 19) and (−15, 28), in standard form, is: x + y = 13
<em><u>Recall:</u></em>
- Equation of a line can be written in standard from as Ax + By = C, where Ax and By are all terms of variable x and y, and C is a constant.
- The equation of a line in point-slope,
, can be rewritten in the standard form.
- Slope (m) =
Given: (−6, 19) and (−15, 28)
<em>Find the </em><em>slope </em><em>(m):</em>
<em />
Write the equation in point-slope form by substituting m = -1 and into
.
- Rewrite in standard form
Therefore, the equation of the line that contains (−6, 19) and (−15, 28), in standard form, is: x + y = 13
Learn more about equation of a line in standard form on: