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andreev551 [17]
3 years ago
14

What is the surface area of the solid that this net can form? A net has 2 rectangles. One rectangle has a base of 25 millimeters

and a height of 21 millimeters. The other rectangle has a base of 41 millimeters and height of 5 millimeters.
Mathematics
2 answers:
hammer [34]3 years ago
6 0

Answer:

730mm²

Step-by-step explanation:

JulijaS [17]3 years ago
5 0

Answer:

S.A = 730mm²

Step-by-step explanation:

Since the solid is made up of two rectangles. Then the surface area (S.A) would be

S.A = area of first rectangle + area of second rectangle

Since the first rectangle has it's base to be 25mm and height to be 21mm, then it's area is

25mm x 21mm = 525mm²

Since the second rectangle has it's base to be 41mm and height to be 5mm, then it's area is

41mm x 5mm = 205mm²

Therefore

S.A = 525mm² + 205mm² = 730mm²

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cross multiply the equation to give you

1= a(2bh+3)

divide both sides by a(2b+3)

answer is 1/2ab+3 = h


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Anuta_ua [19.1K]

Answer:

2/3

Step-by-step explanation:

If you divided 2 by 3, you will get 0.6 repeating.

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The object above is symmetrical through Y = 17 inches Z = 18 inches, and H = 11 inches, what is the area of the object ?
oksian1 [2.3K]

Answer:

let me try

a= 1/2(l×w)

=1/2*17*18

=1/2(306)

A=153

8 0
3 years ago
Please help me AAAAAA
bezimeni [28]

Answer:

45

Step-by-step explanation:

AEF is a similar triangle to ABC. that means it has the same angles, and the sides (and all other lines in the triangle) are scaled from the ABC length to the AEF length by the same factor f.

now, what is f ?

we know this from the relation of AC to FA.

FA = 12 mm

AC = 12 + 28 = 40 mm

so, going from AC to FA we multiply AC by f so that

AC × f = FA

40 × f = 12

f = 12/40 = 3/10

all other sides, heights, ... if ABC translate to their smaller counterparts in AEF by that multiplication with f (= 3/10).

the area of a triangle is

baseline × height / 2

aABC = 500

and because of the similarity we don't need to calculate the side and height in absolute numbers. we can use the relative sizes by referring to the original dimensions and the scaling factor f.

baseline small = baseline large × f

height small = height large × f

we know that

baseline large × height large / 2 = 500

baseline large × height large = 1000

aAEF = baseline small × height small / 2 =

= baseline large × f × height large × f / 2 =

= baseline large × height large × f² / 2 =

= 1000 × f² / 2 = 500 × f² = 500 ×(3/10)² =

= 500 × 9/100 = 5 × 9 = 45 mm²

8 0
3 years ago
The volume of a rectangular box is 330 cubic inches. The length on one side of the top is 11 inches, and the height of the box i
Fiesta28 [93]

Answer: 110 square inches.

Step-by-step explanation:

The volume of a rectangular box would be:

V=length*width*height

In this case, we know the volume, the length and the height, and we don't know the width, so we're going to isolate it:

width=\frac{V}{length*height}

Substituting the data:

width=\frac{330}{11*3} =10in

This width is also the width of the top of the box, so the area of the top would be:

A=length*width\\A=11*10\\A=110in^{2}

5 0
4 years ago
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