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Sati [7]
3 years ago
7

Which of the linear equations represents the graphed line?

Mathematics
2 answers:
goldenfox [79]3 years ago
7 0
The answer is A: y = 3/2x + 1
nasty-shy [4]3 years ago
7 0
I also go with the other person is has to be A
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A shepherd is paid rs.2400 for gazing 18 cows for 5 weeks.How much will be paid for gazing 20 cows for 8 weeks?
lys-0071 [83]

Answer:

Rs. 4266.67(approx) will be paid for gazing 20 cows for 8 weeks.

Explanation:

A shepherd is paid rs. 2400 for gazing 18 cows for 5 weeks .

⇒ Number of money paid for gazing 1 cow for 1 week is, \frac{2400}{18\times 5} =\frac{400}{15}= \frac{80}{3}

then,

for gazing 20 cows for 8 weeks is=  Rs. \frac{80}{3}\times (20\times 8)

Therefore, the amount paid for gazing 20 cows for 8 weeks is, \frac{80 \times 160}{3} = \frac{12800}{3} = Rs. 4266.66667 or Rs. 4266.67(approx)

7 0
3 years ago
use the method of successive differences to determine the next term in the sequence: 4, 14, 82, 268, 657, 1359
IRISSAK [1]
The method of successive differences uses subtraction to the one number to the next and the process goes on until the difference settles constant which is not equal to zero. In this case, the constant difference reaches 25. Reversing the process to get the next term, the answer is 2509.  
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3 years ago
Find the length of the Lm of LM if L is (10,6) and M is (0,-7)
lubasha [3.4K]

Answer:

16.4012194669

simplified: 16.4

Step-by-step explanation:

4 0
3 years ago
One plant from the garden is randomly selected. There is a 30% chance that the plant was purchased this year, and there is a 6%
Juliette [100K]
Answer and workings in the attachment below. Also, do me one big favour. Let me know if it's the answer your teacher or text book ends up giving you. That would give me some satisfaction.

Answer: 80%

7 0
3 years ago
Read 2 more answers
Given that the expression x³_ ax² + bx+c leaves the same remainder when divided by x + 1 or x-2, find 'a' in terms of 'b'.​
goblinko [34]

Answer:

Hi,

a=b+3

Step-by-step explanation:

\begin{array}{c||c|c|c|c}&x^3&x^2&x&1\\---&---&---&---&---\\&1&-a&b&c\\x=-1&&-1&a+1&-a-b-1\\---&---&---&---&---\\&1&-a-1&a+b+1&c-a-b-1\\\end{array}

\begin{array}{c||c|c|c|c}&x^3&x^2&x&1\\---&---&---&---&---\\&1&-a&b&c\\x=2&&2&4-2a&2b+8-4a\\---&---&---&---&---\\&1&2-a&b+4-2a&c+2b+8-4a\\\end{array}

Thus:

c+2b+8-4a=c-a-b-1

3b-3a=-9

<u>a=b+3</u>

5 0
2 years ago
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