Answer:
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Step-by-step explanation:
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To find the answer we simply work out the equation.
cos (75) = 10/x
cos (75) * x = 10. Here, I simply multiplied both sides by x to move x to the left hand side of the equation.
x = 10 / cos (75) Here, I divided cos (75) on both sides to move cos (75) to the right hand side of the equation.
The cosine of 75 is 0.92175127, so, 10 / 0.92175127 = 10.8489137
Answer:
The system of inequalities that represents this situation is:
x+y≥10
6x+4y≤50
Step-by-step explanation:
As the statement says that Laura wants to provide one party favor per person to at least 10 guests, the first inequality would indicate that the number of stuffed animals plus the number of toy trucks should be equal or greater than 10:
x+y≥10
Also, the statement indicates that miniature stuffed animals cost $6.00 each and the toy trucks cost $4.00 each and that Laura has $50. From this, you would have an inequality that indicates that 6 for the number of miniature stuffed animals and 4 for the number of toy trucks would be equal or less than 50:
6x+4y≤50
The answer is that the system of inequalities that represents this situation is:
x+y≥10
6x+4y≤50
Answer:
Month 1 : 0.002988
Month 2: 0.00299692814
Month 3: 0.00300588297
Step-by-step explanation:
Since we're only finding the interest for the first three months, it's easy to do it by performing the simple interest formula. But first, we need divide 3 by 12, since we calculate interest using years. 3/12 = 1/4 = 0.25
The standard simple interest calculation is done by multiplying the starting amount, by the interest, by the time, then dividing by 100 to put it into a percentage.
1 month = 1/12 or approximately 0.083 of the year.
Let's say P = 1. For the first month, it will be 1 x 3.6 x 0.083 = 0.2988 / 100
The second month, (1 + 0.002988) * 3.6 * 0.083 = 0.299692814 / 100
The third month, (1.002988 + 0.00299692814) x 3.6 x 0.083 = 0.300588297/100
Given the initial amount be 1, those would be the periodic interest rate during the first three months.
Consider the exponential function 
By definition, the domain of a function is the set of input argument values for which the function is real and defined.
Let we take 
then 
then 
then 
If we chose larger values of x, we get larger function values.
For example, If we take 
Thus if we choose smaller and smaller values of x. the f unction values will be smaller and smaller functions.
Thus the domain of the function is the set of all real numbers.
Thus the range is limited to the set of positive real numbers. That is, 
If we choose larger values of x, we will get larger function values, as the function values will be larger powers of 2.
If we choose smaller and smaller x values, the function values will be smaller and smaller fractions.
