What is the conversion factor for in^3 to cm^3

The fact that HBO2, a reactive compound, was produced rather than the relatively inert B2O3 was a factor in the discontinuation

Reil [10]

Answer:

1027.62 g

Explanation:

For $B_2H_6$ :-

Mass of $B_2H_6$ = 296.1 g

Molar mass of $B_2H_6$ = 27.66 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{296.1\ g}{27.66\ g/mol}$

$Moles\ of\ B_2H_6= 10.705\ mol$

From the balanced reaction:-

$B_2H_6(g) + 3 O2_{(l)}\rightarrow 2 HBO_2_{(g)}+ 2 H_2O_{(l)}$

1 mole of $B_2H_6$ react with 3 moles of oxygen

Thus,

10.705 mole of $B_2H_6$ react with 3*10.705 moles of oxygen

Moles of oxygen = 32.115 moles

Molar mass of oxygen gas = 31.998 g/mol

Mass = Moles * Molar mass = 32.115 * 31.998 g = 1027.62 g

8 0

3 years ago

The energy produced when nucleons fuse together is called the: Select the correct answer below:

saveliy_v [14]

Answer:

Option C (nuclear binding energy) is the appropriate choice.

Explanation:

At either the nuclear scale, the nuclear binding energy seems to be the energy needed to remove and replace a structure of the atom itself into the characterize elements (to counteract the intense nuclear arsenal).
Nuclear warheads (bargaining power) bind everything together neutrons as well as protons within an elementary particle.

Some other options in question aren't relevant to the particular instance. So that the option preceding will also be the right one.

7 0

2 years ago

In the reaction, A → Products, the rate constant is 3.6 × 10−4 s−1. If the initial concentration of A is 0.548 M, what will be t

Arada [10]

Answer:

$\large\boxed{\large\boxed{0.529M}}$

Explanation:

Since the rate constant has units of s⁻¹, you can tell that the order of the reaction is 1.

Hence, the rate law is:

$r=d[A]/dt=-k[A]$

Solving that differential equation yields to the well known equation for the rates of a first order chemical reaction:

$[A]=[A]_0e^{-kt}$

You know [A]₀, k, and t, thus you can calculate [A].

$[A]=0.548M\times e^{-3.6\cdot 10^{-4}/s\times99.2s}$

$[A]=0.529M$

7 0

3 years ago

1. A part of a neuron is a(n) A. nerve B. cell body C. receptor D. acetylcholine

katovenus [111]

A neuron has 4 basic part the dendrites the cell body
I think the answer is b.the cell body
but the brain is made up of about 86 billion nerve cells also called neuron

3 0

2 years ago

Fe + H2SO4 = Fe2(SO4)3 + H2

a_sh-v [17]

C (667) that’s the answer boiii

5 0

3 years ago