Answer:
Option D. 17.5
Explanation:
Equiibrium is: CO + 2H₂ ⇄ CH₃OH
1 mol of CO is in equibrium with 2 moles of hydrogen in order to make, methanol.
Initially we have 0.42 moles of CO and 0.42 moles of H₂
If 0.29 moles of CO remained, (0.42 - 0.29) = 0.13 moles have reacted.
So in the equilibrium we may have:
0.29 moles of CO, and (0.42 - 0.13 . 2) = 0.16 moles of H₂
Ratio is 1:2, if 0.13 moles of CO haved reacted, (0.13 . 2) moles have reacted of hydrogen
Finally 0.13 moles of methanol, are found after the equilibrium reach the end.
Let's make expression for KC: [Methanol] / [CO] . [Hydrogen]²
0.13 / (0.29 . 0.16²)
Kc = 17.5
There is no question to your answers please list the question and I will be able to help.
As the atomic number increases the atomic radius increases since it's adding more electrons to the outermost shell
<h3><u>Answer;</u></h3>
160 g
<h3><u>Explanation;</u></h3>
1 mole of a compound contains a mass equivalent to the relative formula mass of that particular compound.
the formula of iron oxide is Fe2O3
R.A.M of Iron = 56 , while that of oxygen is 16
RFM = (56 ×2) + (16 ×3)
= 112 + 48
= 160
Therefore, 1 mole of Iron oxide contains 160 g
the answer to your question is glucose