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Andrej [43]
3 years ago
14

What is the mass of 3.01 x 10^21 atoms of Co

Chemistry
1 answer:
OlgaM077 [116]3 years ago
5 0

Answer:

0.295 g Co

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

3.01 × 10²¹ atoms Co

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Co - 58.93 g/mol

<u>Step 3: Convert</u>

<u />3.01 \cdot 10^{21} \ atoms \ Co(\frac{1 \ mol \ Co}{6.022 \cdot 10^{23} \ atoms \ Co} )(\frac{58.93 \ g \ Co}{1 \ mol \ Co} ) = 0.294552 g Co

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

0.294552 g Co ≈ 0.295 g Co

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Answer:

=8 atoms

Explanation:

In (NH4)2C2O4 there are four moles of Hydrogen in the compound (NH4), but there two molecules of (NH4) in this compound.  That's what the 2 in (NH4)2 means, so multiply 4 x 2 = 8.

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Explain how the hydrogen ion concentration gradient is generated
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Once three protons have entered the matrix space, there is enough energy in the ATP synthase complex to synthesize one ATP. In this way, the energy in the hydrogen ion gradient is used to make ATP. ... The mitochondrial hydrogen ion gradient is generated as electrons pass through three membrane complexes.

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2 years ago
What rule/principle states that electrons fill orbitals from lowest energy to highest enegery?​
castortr0y [4]

Answer:

The Aufbau Principle

Explanation:

In the ground state of an atom or ion, electrons fill atomic orbitals of the lowest available energy level before occupying higher-energy levels.

7 0
3 years ago
A lithium flame has a characteristic red color due to emissions of wavelength 671 nm. What is the mass equivalence of 1 mol of p
e-lub [12.9K]

Answer:

1.98x10⁻¹² kg

Explanation:

The <em>energy of a photon</em> is given by:

  • E= hc/λ

h is Planck's constant, 6.626x10⁻³⁴ J·s

c is the speed of light, 3x10⁸ m/s

and λ is the wavelenght, 671 nm (or 6.71x10⁻⁷m)

  • E = 6.626x10⁻³⁴ J·s * 3x10⁸ m/s ÷ 6.71x10⁻⁷m = 2.96x10⁻¹⁹ J

Now we multiply that value by <em>Avogadro's number</em>, to <u>calculate the energy of 1 mol of such protons</u>:

  • 1 mol =  6.023x10²³ photons
  • 2.96x10⁻¹⁹ J *  6.023x10²³ = 1.78x10⁵ J

Finally we <u>calculate the mass equivalence</u> using the equation:

  • E=m*c²
  • m=E/c²
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6 0
3 years ago
Determine the boiling point of a 3.70 m solution of phenol in benzene. Benzene has a boiling point of 80.1°C and a boiling point
xeze [42]

Answer: The boiling point of a 3.70 m solution of phenol in benzene is 89.5^0C

Explanation:

Elevation in boiling point:

\Delta T_b=i\times k_b\times m

where,

\Delta T_b = change in boiling point

i= vant hoff factor = 1 (for benzene which is a non electrolyte )

k_b = boiling point constant = 2.53^0C/kgmol

m = molality = 3.70

T_{solution}-T_{solvent}=i\times k_b\times m

T_{solution}-80.1^0C=1\times 2.53\times 3.70

T_{solution}=89.5^0C

Thus  the boiling point of a 3.70 m solution of phenol in benzene is 89.5^0C

8 0
3 years ago
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