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torisob [31]
3 years ago
14

Would you expect the Mg3[Cr(CN)6]2 to be diamagnetic or paramagnetic? Explain your reasoning.

Chemistry
1 answer:
bixtya [17]3 years ago
5 0

Answer:

paramagnetic

Explanation:

The complex ion is : [Cr(CN)₆]³⁻

Oxidation state of Cr in [Cr(CN)₆]³⁻ is:

x + (-1)6 = -3

x = +3

CN⁻ is a strong field ligand which can result in  pairing of the electrons.

The electronic configuration of Cr is:

1s²2s²2p⁶3s²3p⁶3d⁵4s¹

The electronic configuration of Cr³⁺ is:

1s²2s²2p⁶3s²3p⁶3d³

<u>These 3 electrons will be singly present in the 3 degenerate t₂g orbitals and per Hund's rule, pairing will not occur in the same level energy orbitals. So , no. of unpaired electrons will be 3 and the complex will be paramagnetic.</u>

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Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimen
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Answer: Rate law=k[A]^1[B]^2, order with respect to A is 1, order with respect to B is 2 and total order is 3. Rate law constant is 3L^2mol^{-2}s^{-1}

Explanation: Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Rate=k[A]^x[B]^y

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y = order with respect to A

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a) From trial 1: 1.2\times 10^{-2}=k[0.10]^x[0.20]^y    (1)

From trial 2: 4.8\times 10^{-2}=k[0.10]^x[0.40]^y    (2)

Dividing 2 by 1 :\frac{4.8\times 10^{-2}}{1.2\times 10^{-2}}=\frac{k[0.10]^x[0.40]^y}{k[0.10]^x[0.20]^y}

4=2^y,2^2=2^y therefore y=2.

b) From trial 2: 4.8\times 10^{-2}=k[0.10]^x[0.40]^y    (3)

From trial 3: 9.6\times 10^{-2}=k[0.20]^x[0.40]^y   (4)

Dividing 4 by 3:\frac{9.6\times 10^{-2}}{4.8\times 10^{-2}}=\frac{k[0.20]^x[0.40]^y}{k[0.10]^x[0.40]^y}

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Thus rate law is Rate=k[A]^1[B]^2

Thus order with respect to A is 1 , order with respect to B is 2 and total order is 1+2=3.

c) For calculating k:

Using trial 1:  1.2\times 10^{-2}=k[0.10]^1[0.20]^2

k=3 L^2mol^{-2}s^{-1}.



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