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laiz [17]
3 years ago
11

Please help 10 points asap​

Chemistry
2 answers:
AnnyKZ [126]3 years ago
3 0

Answer:

opposite

Explanation:

Wewaii [24]3 years ago
3 0

Answer:

opposite

Explanation:

cu9c9ucoucucpucfpufupfpucupvpjvpucu

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Which of the following is not a way in which humans direct
Pie

Answer:

its d

Explanation:

5 0
4 years ago
Density is the ratio of a substance ___ to its volume <br> A. Force B. Mass C. Thickness D. Weight
Svetach [21]

Answer:

Density is the ratio of a substance mass to its volume

hope it helps

plz mark brainliest :)

3 0
4 years ago
You want to prepare 500.0 mL of 1.000 M KNO3 at 20°C, but the lab (and water) temperature is 24°C at the time of preparation. Ho
timama [110]

Explanation:

As per the given data, at a higher temperature, at 24^{o}C, the solution will occupy a larger volume than at 20^{o}C.

Since, density is mass divided by volume and it will decrease at higher temperature.

Also, concentration is number of moles divided by volume and it decreases at higher temperature.

At 20^{o}C, density of water=0.9982071 g/ml  

Therefore, \frac{concentration}{density} will be calculated as follows.

                 = \frac{C_{1}}{d_{1}}

                 = \frac{1.000 mol/L}{0.9982071 g/ml}

                 = 1.0017961 mol/g  

At 24^{o}C, density of water = 0.9972995 g/ml

Since, \frac{concentration}{density} = \frac{C_{2}}{d_{2}}

                           = \frac{C_{2}}{0.9972995}

Also,             \frac{C_{1}}{d_{1}} = \frac{C_{2}}{d_{2}}

so,                   1.0017961 mol/g = \frac{C_{2}}{0.9972995}

                      C_{2} = 1.0017961 \times 0.9972995

                                  = 0.9990907 mol/L

Therefore, in 500 ml, concentration of KNO_{3} present is calculated as follows.

             C_{2} = \frac{concentration}{volume}

               0.9990907 mol/L = \frac{concentration}{0.5 L}  

               concentration = 0.49954537 mol

Hence, mass (m'') = 0.49954537 mol \times 101.1032 g/mol = 50.5056 g       (as molar mass of KNO_{3} = 101.1032 g/mol).

Any object displaces air, so the apparent mass is somewhat reduced, which requires buoyancy correction.

Hence, using Buoyancy correction as follows,

                      m = m''' \times \frac{(1 - \frac{d_{air}}{d_{weights}})}{(1 - \frac{d_{air}}{d})}}

where,          d_{air} = density of air = 0.0012 g/ml

                     d_{weight} = density of callibration weights = 8.0g/ml                      

                     d = density of weighed object

Hence, the true mass will be calculated as follows.

           True mass(m) = 50.5056 \times \frac{(1 - \frac{0.0012}{8.0})}{(1 - (\frac{0.0012}{2.109})}

             true mass(m) = 50.5268 g

                                  = 50.53 g (approx)

Thus, we can conclude that 50.53 g apparent mass of KNO_{3} needs to be measured.

8 0
3 years ago
The lifetime of a human is approximately 71 years. Which of the following is this number closest to? Remember the following conv
jarptica [38.1K]

2.2Giga

Explanation:

Given that the number of years = 71years

We need to convert this to seconds;

   60s = 1 min

    60 min = 1hr

   24hr = 1 day

   7 days = 1 week

    52 weeks = 1yr

 71 years x \frac{52weeks }{1yr}  x \frac{7 days}{1 week } x \frac{24hr}{ 1day }  x \frac{60min}{1hr} x \frac{60s}{1min}  = 2,232,921,600‬s

This value is 2.2 x 10⁹s  = 2.2Giga

learn more:

Conversion brainly.com/question/555814

#learnwithBrainly

7 0
3 years ago
Find the empirical formula of each of the following compounds. Given mass or for each element in a sample of the compound 3,611
KengaRu [80]

Answer:

CaCl₂  

Step-by-step explanation:

The <em>empirical formula</em> is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles.

So, our job is to calculate the molar ratio of Ca to Cl.

Data:

Mass of Ca = 3.611 g

Mass of Cl = 6.389 g

Calculations

Step 1. <em>Calculate the moles of each element </em>

Moles of Ca = 3.611 g Ca × (1 mol Ca/(40.08 g Ca)= 0.090 10 mol Ca

Moles of Cl = 6.389 g Cl  

Step 2. <em>Calculate the molar ratio of the elements </em>

Divide each number by the smallest number of moles

Ca:Cl = 0.090 10:0.1802 = 1:2.000

Step 3. Round the molar ratios to the nearest integer

Ca:Cl = 1:2.000 ≈ 1:2


Step 4: <em>Write the empirical formula </em>

EF = CaCl₂

8 0
3 years ago
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