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Blababa [14]
3 years ago
7

Which transition represents a time when water molecules are moving closer together? Frost forms on a window pain. Sleet turns to

rain. Dew forms on the grass. A puddle disappears.
Chemistry
1 answer:
Anettt [7]3 years ago
4 0
The correct answer here is C. Dew forms on the grass.

Water is a polar substance, which means it has many unique properties. One of which, is its ability to adhere and cohere to surfaces and substances. This particular question is asking about the cohesive properties of water, meaning it’s ability to stick to itself (through bonding.) The only answer choice that represents a situation where water is linking up with other molecules of water are dew drops. The water comes together using cohesion to form the drop and hen the water’s high surface tension properties meet the dew drop’s shape. The other answer choices describe alternate processes like: freezing, melting, and evaporation, respectively.

I hope this helps! :)
You might be interested in
Which law relates to the ideal gas law?
professor190 [17]

<u>Answer:</u> The law that related the ideal gas law is \frac{V_1}{n_1}=\frac{V_2}{n_2}

<u>Explanation:</u>

There are 4 laws of gases:

  • <u>Boyle's Law:</u> This law states that pressure is inversely proportional to the volume of the gas at constant temperature.  

Mathematically,

P_1V_1=P_2V_2

  • <u>Charles' Law:</u> This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

  • <u>Gay-Lussac Law:</u> This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

  • <u>Avogadro's Law:</u> This law states that volume is directly proportional to number of moles at constant temperature and pressure.

Mathematically,

\frac{V_1}{n_1}=\frac{V_2}{n_2}

Hence, the law that related the ideal gas law is \frac{V_1}{n_1}=\frac{V_2}{n_2}

8 0
3 years ago
Read 2 more answers
Please help.This is due tomorrow.It's worth 2 grades.Please help.God bless u.Please and thankyou so much.
Daniel [21]

Answer:

1. False - compression

2. True

3. False - transform faults

4. False - horizontally

5. True

6. False- perpendicular

7. False - away from

8. False - increase

9. True

10. True

Explanation:

1. Mountains, oceanic trenches, and rift valleys are created by tension and compression stress. They are formed by divergent and convergent boundaries. Compression stress occurs when plates are pushing against each other, while tension stress occurs when the plates are pulling away from each other.

**Shear stress happens when the plates grind against each other. Often found in transform boundaries.

2. Transform faults happen when two plates glide or slide against each other. These areas are called transform boundaries. Transform faults occur in the ocean. When these boundaries are formed on land, they are called strike-slip faults.

3. Shear stress that occur in transform boundaries produce transform faults. These faults are usually identified by long faults and ridges. Sometimes small ponds form in the cracks due to deposition.

*** Rift valleys are produced by divergent boundaries or tension stress, when the plates are pulled apart.

4. Transform boundaries are formed when two plates slides against each other. Transform faults are formed in these boundaries and the movement of the plates are horizontal.

*** They do not move vertically.

5-6. Mid-oceanic ridges are segmented or divided by transform faults. The transform faults in the mid-oceanic ridges are perpendicular to the oceanic ridges. They separate them into distinct segments and can run across for hundreds of kilometers

7. New faults form as they move away from the ridges. Mid oceanic ridges are formed when the plates move apart, pushing the seafloor outwards and along with that, the transform faults. When new crust however overlaps the transform fault, they stop moving against each other, and start moving side by side, creating a crack.

8. Transform faults increase in size as long as the plates continue to move. The areas of transform faults, especially in the surface create earthquake faults.

9. Faults at the surface can be part of a larger underground system. Some faults can cut across continental crusts. These faults are created by different geological processes, like compression stress from convergent boundaries, tension stress from divergent boundaries, and shear stress from transform boundaries.

10. Fault zones are areas where you can find different faults formed, relatively close to each other. The faults in fault zones can be shallow or deeper like the fault zone Sierra Madre.

6 0
3 years ago
1. Why does light have different effects on various materials?
Debora [2.8K]
Light basically evaporates pigments such as colored paper. Exposed pigment fading is kind of like getting colored paper wet. It will fade and bleed.
4 0
3 years ago
Read 2 more answers
The pressure of a 70.0L sample of gas is 600 mm Hg at 20.0C. If the temperature drops to 15.0C and the volume expands to 90.0L,
Mekhanik [1.2K]

Answer:

458.7 mmHg

Explanation:

Step 1:

Data obtained from the question. This includes:

Initial volume (V1) = 70L

Initial pressure (P1) = 600 mmHg

Initial temperature (T1) = 20°C

Final temperature (T2) = 15°C

Final volume (V2) = 90L

Final pressure (P2) =...?

Step 2:

Conversion of celsius temperature to Kelvin temperature.

This is illustrated below:

T(K) = T (°C) + 273

Initial temperature (T1) = 20°C

Initial temperature (T1) = 20°C + 273 = 293K

Final temperature (T2) = 15°C

Final temperature (T2) = 15°C + 273 = 288K

Step 3:

Determination of the new pressure of the gas.

The new pressure of the gas can be obtained by using the general gas equation as shown below:

P1V1/T1 = P2V2/T2

600 x 70/293 = P2 x 90/288

Cross multiply to express in linear form

P2 x 90 x 293 = 600 x 70 x 288

Divide both side by 90 x 293

P2 = (600 x 70 x 288) / (90 x 293)

P2 = 458.7 mmHg

Therefore, the new pressure of the gas is 458.7 mmHg

5 0
3 years ago
Iron has a density of 7.9 g/cm3. The volume of a regular cylinder is V =πr2h. An iron cylinder has a height of 3.00 m and a mass
Sedaia [141]
Hfhsnebrjicjcbdnd hope this helps
6 0
3 years ago
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