HELP!!!!!!

Mathematics

2 answers:

maria [59]3 years ago

6 0

However many X's are on the speed, that's how many cars had that speed. For example on the chart, 29 has one X above it; therefore, there was one car that had the speed 29 mph. :)

aliina [53]3 years ago

6 0

31 had 0
32 had 0
33 had 2
34 had 4
35 had 5
36 had 3
37 had 0
38 had 2
39 had 2
40 had 1

You might be interested in

Write two decimals that are equivalent to 0.9

Maurinko [17]

0.90 and I think .9 is another I'm not sure but I tried

6 0

2 years ago

Read 2 more answers

Determine the quotient and remainder F(x)=6x^4+12x^3+24x^2+<br> 23x+18 is divided by g(x)=2x^2+2x+4

Mekhanik [1.2K]

The only way to do this one is by long division which I can't figure out how to show here. There are some great examples online if you google long division with polynomials.

The answer is 3x^2+3x+3 with a remainder of 5x+6 who's is usually shown as (5x+6)/2x^2 +2x+4 which was the divisor g(x).

8 0

3 years ago

It takes an older employee 13 hours to shovel the snow from a sidewalk, but a younger employee can shovel the same sidewalk in 1

Ket [755]

Work in rates per hour. These rates can then be added to form an equation

1/13 + 1/10 = 1/x where x is the time for both working together

multiply thru by 130x:-

10 x+ 13 x = 130

x = 130/23 = 5.65 hours or about 6 hours 39 minutes

7 0

3 years ago

58x -160 = 16 ecuacion diofantica(diophantine ecuation)

Rus_ich [418]

Answer: x = 88/29

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

A couple is thinking about having 3 children. Assume that each child is equally likely to be a girl or a boy. What is the probab

nignag [31]

Answer:

O.375

Step-by-step explanation:

We will start with the second part of the question, listing out all of the possible combinations that can occur from this data set. There is a 50/50 chance of having a girl or a boy, and there are three children. For now we'll use B to represent a boy and G for a girl. It goes as follows:

(B, B, B), (B, B, G), (B, G, B), (B, G, B), (B, G, G), (G, B, B), (G, B, G), (G, G, B), (G, G, G)

I often find it easy to write out a branch diagram to help me visualize this problem and make sure I have all possibilities. (See attached image)

Count the total number of combinations (9). Next, count the number that include exactly 2 girls (4). With this information, we now know that there is a 4 out of 9 chance of having exactly 2 girls and one boy. 4/9 is in simplest form, so all you have to do is find the percentage 44.444%

Answer:

C or 37.5

5 0

2 years ago