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2 years ago

6

If side BC is labeled 15 cm, and NL is labeled (x + 8), what is the value of x?

2 answers:

jarptica [38.1K]2 years ago

6 0

Answer:

7?

Step-by-step explanation:

I hope this is correct and it helps!

kramer2 years ago

5 0

Answer :7
Hope this helps

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Factor 4x 2 + 12x + 5 . (2x + 5)(2x + 1)

Juliette [100K]

Factor
in form
ax²+bx+c form
use the ac method
1. mulitply a and c
2. factor the result such that the 2 factors add to b
3. split b into those 2 factors
4. group the terms
5. undistribute common factors
6. undistribute again

first multiply ac
4 times 5=20
now
what 2 numbers multiply to 20 and add to 12
2 and 10
4x²+2x+10x+5
group
(4x²+2x)+(10x+5)
undistribute
2x(2x+1)+5(2x+1)
undistribute the (2x+1)
(2x+1)(2x+5) is factored form whih you have there, nice

8 0

3 years ago

Quadrilateral PAID is a rectangle whose diagonals have the endpoints P(-3, -2)I(4, -7) and A(4, -2)D(-3, -7). Find the diagonals

BARSIC [14]

Answer:

$(0.5,-4.5)$

Step-by-step explanation:

The given rectangle has diagonals have the endpoints P(-3, -2) ,I(4, -7) and A(4, -2) ,D(-3, -7)

The diagonals of the rectangle bisect each other so we use the midpoint formula to find their point of intersection.

The midpoint formula is;

$(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

We use any pair of endpoints of the diagonals to find the point of intersection.

Using A(4, -2) ,D(-3, -7)

$(\frac{4+-3}{2},\frac{-2+-7}{2})$

$(\frac{1}{2},\frac{-9}{2})$

or

$(0.5,-4.5)$

7 0

3 years ago

Cos (90-theta) • cosec90-theta) =tano. How?

denis-greek [22]

Answer:

<u>______________________________________________________</u>

<u>TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-</u>

For any right angled triangle with one angle α ,

$\cos (90 - \alpha ) = \sin \alpha$ or $\sin(90 - \alpha ) = \cos\alpha$

$cosec \: (90 - \alpha ) = \sec\alpha$ or $\sec(90 - \alpha ) = cosec\:\alpha$

<u>SOME GENERAL TRIGNOMETRIC FORMULAS :-</u>

<u></u> $\sin \alpha = \frac{1}{cosec \: \alpha }$ or $cosec \: \alpha = \frac{1}{\sin \alpha }$

<u></u> $\cos \alpha = \frac{1}{\sec \alpha }$ or $\sec \alpha = \frac{1}{\cos \alpha }$

<u>______________________________________________________</u>

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

$\cos (90 - \alpha ) \times cosec(90 - \alpha )$

$=> sin\alpha \times \sec\alpha$

$=> \sin\alpha \times \frac{1}{\cos\alpha }$

$=> \frac{\sin\alpha }{\cos\alpha }$

$=> \tan\alpha$ = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

3 0

3 years ago

2.74 as a mix number

Inga [223]

Answer:

2 74/100

Step-by-step explanation:

6 0

3 years ago

Pls help this is important

Svet_ta [14]

Answer:

<h2>C is the answer </h2>

Step-by-step explanation:

<h2>5/4 is the answer</h2>

8 0

3 years ago

Read 2 more answers