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yuradex [85]
2 years ago
7

One of Canada's tallest trees is a Douglas fir on Vancouver Island. The angle of elevation measured by an observer who is 78 m f

rom the base of the tree is 50 degrees. How tall is this tree to the nearest meter?
Mathematics
1 answer:
kkurt [141]2 years ago
6 0

Answer:

93 m

Step-by-step explanation:

We solve this above question using the Trigonometric function of Tangent

tan θ = Opposite/Adjacent

Opposite = Height of the tree = ?? = x

Adjacent = Distance from the base of the tree = 78m

θ = 50°

Hence:

tan 50 = x/78

Cross Multiply

x = tan 50 × 78

x = 92.956780222m

Approximately = 93 m

Therefore, the tree is 93 meters tall

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What is the value of k?​
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Hope this helps :)

Have a nice day!

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Calculate the distance between (0,3) and (3,10) to 1 decimal place
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7 0
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Type the correct answer in each box. Round the vector's magnitude to the nearest tenth.
Mama L [17]

Component form of u is (-18,13) and The magnitude of u is 22.2

<h3>What is a vector?</h3>

A vector is a two-dimensional entity with both magnitude and direction. A vector can be visualized geometrically as a directed line segment.

The component form of a vector is an ordered pair that describes the change in x and y values

This is mathematically expressed as (Δx, Δy) where Δx=x₂-x₁ and Δy=y₂-y₁

Given ;

Initial points of the vector as (14,-6)

The terminal point of the vector is (-4,7)

Here x₁=14,x₂=-4, y₁=-6,y₂=7

The component form of the vector u is (-4-14,7--6) =(-18,13)

Finding the Magnitude of the vector

u=√(x₂-x₁)²+(y₂-y₁)²

u=√-18²+13²

u=√324+169

u=√493

u=22.2

Therefore the Component form of u is (-18,13) and The magnitude of u is 22.2

To know more about vectors follow

brainly.com/question/25705666

#SPJ1

3 0
1 year ago
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