Question

What is an equation of the line that passes through the point (-6,5) and is parallel

Answer 1

Answer:

y=1/3x+7

Step-by-step explanation:

Hi there!

We're given the equation x-3y=21 and we want to find the equation of the line parallel to x-3y=21 that passes through (-6,5)

Parallel lines have the same slopes, but different y intercepts

So we need to find the slope of x-3y=21

To do that, we can convert x-3y=21 from standard form (ax+by=c where a, b, and c are integers) to slope-intercept form (y=mx+b, where m is the slope and b is the y intercept).

We'll need to isolate y onto one side

subtract x from both sides

-3y=-x+21

divide both sides by -3

y=1/3x-7

1/3 is in the place where m is, so 1/3 is the slope of the line

it's also the slope of the line parallel to x-3y=21

here's the equation of the line parallel to x-3y=21 so far:

y=1/3x+b

we need to find b

as the line passes through (-6,5), we can use it to solve for b

substitute -6 as x and 5 as y

5=1/3(-6)+b

multiply

5=-2+b

add 2 to both sides

7=b

Substitute 7 as b into the equation

y=1/3x+7

Hope this helps!