Yes because when you divide 27 by 51, you get 0.529411765. When you divide 18 by 34you get the same answer.
4(c+2)<4c+10
4c+8<4c+10
-4c -4c
--------------------
8<10
Which gives you No Solution.
Answer:
yES 2:3
Step-by-step explanation:
The sides are the same length
Answer:
Step-by-step explanation:
Let n = the smaller of the two numbers, and since the other number is 5 more than twice the smaller number n, then ...
Let 2n + 5 = the second and larger number.
Since the sum of the two unknown numbers is 26, then we can write the following equation to be solved for n as follows:
n + (2n + 5) = 26
n + 2n + 5 = 26
Collecting like-terms on the left, we get:
3n + 5 = 26
3n + 5 - 5 = 26 - 5
3n + 0 = 21
3n = 21
(3n)/3 = 21/3
(3/3)n = 21/3
(1)n = 7
n = 7
Therefore, ...
2n + 5 = 2(7) + 5
= 14 + 5
= 19
CHECK:
n + (2n + 5) = 26
7 + (19) = 26
7 + 19 = 26
26 = 26
Therefore, the two desired numbers whose sum is 26 are indeed 7 and 19.
Answer: The answer is -9
Step-by-step explanation:
7z<-28= -9
Because we take the -28 and add 19 because that's the common denominator and we come up with -9
