Question 3 of 5
2 answers:
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Answer:
a) 8/10
b)
c) Independent events
Step-by-step explanation:
The given information are;
The proportion of women than carries a mutation of the BRCA gene, P(A) = 1/600
The proportion of women in which the mutation develops breast cancer, P(B) = 8/10
a) The probability that a randomly selected woman will develop breast cancer given that she has a mutation of the BRCA gene is given as follows;
1 × P(B) = 1 × 8/10 = 8/10
b) The probability, P that a randomly selected woman woman will carry the mutation of the BRCA gene and will develop breast cancer is given as follows;
P(A) × P(B) = 1/600×8/10 = 1/750 =
c) The events are dependent
Given that P(A) × P(B) = P(A∩B), the events of carrying the mutation and developing Breast cancer are independent events.
Answers:
a = -6/37
b = -1/37
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Explanation:
Let's start things off by computing the derivatives we'll need
Apply substitution to get
I've factored things in such a way that we have something in the form Msin(x) + Ncos(x), where M and N are coefficients based on the constants a,b.
The right hand side is simply sin(x). So we want that cos(x) term to go away. To do so, we need the coefficient (a-6b) in front of that cosine to be zero
a-6b = 0
a = 6b
At the same time, we want the (-6a-b)sin(x) term to have its coefficient be 1. That way we simplify the left hand side to sin(x)
-6a -b = 1
-6(6b) - b = 1 .... plug in a = 6b
-36b - b = 1
-37b = 1
b = -1/37
Use this to find 'a'
a = 6b
a = 6(-1/37)
a = -6/37