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3 years ago

May you please help me with this

Mathematics

1 answer:

steposvetlana [31]3 years ago

7 0

Answer:

ratio of a is 44:56, ratio of b is 97:3

fraction of a is 44/100, fraction of b is 97/100

decimal of a is 0.44, decimal of b is 0.97

percent of a is 97%, and percent of b is 97%

if this is wrong im so sorry :()()()()(

step-by-step explanation:

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Regan earned a total of 15 by selling 5 cups of lemonade how many cups of lemonade does Reagan need to sell and altar on $42 ass

Gemiola [76]

Idk if its right sorry

8 0

3 years ago

ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions

77julia77 [94]

Answer:

C. It has been stretched horizontally.

Step-by-step explanation:

According to the diagram, the parabola has not been reflected in any way, nor has it been translated, since the parabola is pointing up in a smile, and the vertex is still at the origin.

The parabola does appear to be stretched, since the parent function had points at (1, 1), and (2, 4), but this parabola does not contain those points.

Since the parabola appears to be flatter than the parent function, we can say that C. It has been stretched horizontally.

Hope this helps!

3 0

3 years ago

Read 2 more answers

If 10^2y = 25, then 10^-y equals: (a) -1/5 (b) 1/625 (c) 1/50 (d) 1/25 (e) 1/5

Gemiola [76]

<h3>given:</h3>

$10 ^{2y} = 25$

${10}^{y} = .......$

<h3>solution:</h3>

$10 ^{2y} = 25$

$(10y {)}^{2} = {5}^{2}$

$10y = 5$

$\frac{1}{ {10}^{y} } = \frac{1}{5}$

${10}^{ - y} = \frac{1}{5}$

therefore, the correct answer is option E.

8 0

2 years ago

Read 2 more answers

Assume that in a particular military exercise involving two units, Red and Blue, thereis a 60 % chance that the Red unit will su

Marysya12 [62]

Answer: a) There are 42% chances that both units will meet their objectives.

b) There are 88% chances that one or the other but not both of the units will be successful.

Step-by-step explanation:

Since we have given that

Probability that the Red unit will successfully meet its objectives = 60% = P(R)

Probability that Blue unit will successfully meet its objectives = 70% = P(B)

Probability that only Red unit will be successful = P(only Red) = 18%

As we know that

$P(only\ red)=P(R)-P(R\cap B)\\\\0.18=0.60-P(R\cap B)\\\\0.18-0.60=-P(R\cap B)\\\\-0.42=-P(R\cap B)\\\\P(R\cap B)=42\%$

Hence, there are 42% chances that both units will meet their objectives.

the probability that one or the other but not both of the units will be successful is given by

$P(R\cup B)=P(R)+P(B)-P(R\cap B)\\\\P(R\cup B)=0.60+0.70-0.42\\\\P(R\cup B)=0.88\\\\P(R\cup B)=88\%$

Hence, there are 88% chances that one or the other but not both of the units will be successful.

6 0

3 years ago

Solve for a 6(a+3)=18+6a

Dominik [7]

Expand

(6a + 18 = 18 + 6a)

Cancel 6a on both sides

(18 = 18)

Since both sides are equal, there are infinitely many solutions.

4 0

3 years ago