Answer:
the magnitude and direction of the uniform electric field is 1846.38 N/C and UPWARD respectively
Explanation:
Given the data in the question;
mass m = 1.30 g = 1.30 × 10⁻³ kg
Charge q = +6.90 µC = 6.90 × 10⁻⁶ C
we know that; g = 9.8 m/s
assuming gravity and the electrostatic force are the only forces exerted on the particle, hence the relation is;
F = mg and F = Eq
so
mg = Eq
make E subject of formula
E = mg / q
so we substitute
E = [ (1.30 × 10⁻³) × 9.8 ] / 6.90 × 10⁻⁶
E = 0.01274 / 6.90 × 10⁻⁶
E = 1846.38 N/C
Since the charge is positive ( + ), { direction is Upward }
Therefore, the magnitude and direction of the uniform electric field is 1846.38 N/C and UPWARD respectively
Answer:
v = 1.6 m/s
Explanation:
Given that,
Distance, d = 72 m
Time taken, t = 45 s
We need to find their average velocity. Average velocity of an object is given by total distance divided by total time taken.
So, their average velocity is 1.6 m/s.
KE = 1/2mv^2
m = 2000
v = 30m/s
1/2*2000*30^2=
1000*900 = 900,000kgm^2/s^2
Answer:
The acceleration is
Explanation:
From the question we are told that
The angle which the inclined plane make with horizontal is
The frictional coefficients are and
The force acting on the crate is mathematically represented as
Here f is the net force at which the crate is sliding down the plane which is mathematically represented as
is the force due to weight which is mathematically represented as
and the force due to friction which is mathematically represented as
So
substituting values
Answer:
B) T > ma.
Explanation:
To solve this problem, we have to analyze the forces acting in the horizontal direction.
In the horizontal direction, we have:
- The horizontal component of the tension in the wire, , where T is the magnitude of the tension and the angle that the wire makes with the horizontal
Since this is the only force acting on the box in the horizontal direction, this is also the net force, so it is equal to the product of mass and acceleration (Newton's second law of motion):
where
m is the mass of the box
a is the acceleration
We can rewrite the equation as
The angle in this problem is , so
Therefore, the correct option is
B) T > ma.