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3 years ago

Weathering and Erosion are in constant motion, continuously reshaping the earth's surface. True False

Physics

2 answers:

SashulF [63]3 years ago

6 0

Answer:

true

Explanation:

Natalija [7]3 years ago

5 0

Answer:

True

Explanation:

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Two protons are 1 × 10−10 m apart (about one atomic radius). Which interaction between two protons is stronger, the gravitationa

anastassius [24]

Answer: The electric repulsion between the two protons is stronger than the gravitational attraction.

Explanation: Please see the attachments below

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3 years ago

Explain this quote "ambition beats genius 99% of the time. "

klasskru [66]

Answer:

The idea that hard work is the most important aspect of new inventions existed before Edison gave his quote, however.

The idea behind this quote is that it is easy to have a good idea, or a creative insight. However, to follow through with that idea, and turn it into a reality, takes a level of patience and dedication that few people have.

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3 years ago

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I dropped an apple (mass 0.1kg) from the window because i'm weird. (15m above the ground). How fast was it going when it hit the

Olegator [25]

Answer:

I think the answer is 1 m per second.

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2 years ago

The kinetic theory states that the particles in matter are always in?

OlgaM077 [116]

Motion is the correct word that fits in.
Hope this helps.

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3 years ago

a projectile is fired in such away that its horizontal range is equal to three times its naximum height.what is the angle of pro

finlep [7]

Answer:

$\theta=53.13^o$

Explanation:

<u>2-D Projectile Motion</u>

In 2-D motion, there are two separate components of the acceleration, velocity and displacement. The horizontal component has zero acceleration, while the acceleration in the vertical direction is always the acceleration due to gravity. The basic formulas for this type of movement are

$V_x=V_{ox}=V_ocos\theta$

$V_y=V_{oy}-gt=V_osin\theta-gt$

$x=V_{ox}t$

$\displaystyle y=y_o+V_{oy}t-\frac{gt^2}{2}$

$\displaystyle x_{max}=\frac{2V_{ox}V_{oy}}{g}$

$\displaystyle y_{max}=\frac{V_{oy}^2}{2g}$

The projectile is fired in such a way that its horizontal range is equal to three times its maximum height. We need to find the angle \theta at which the object should be launched. The range is the maximum horizontal distance reached by the projectile, so we establish the base condition:

$x_{max}=3y_{max}$