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3 years ago

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Consider the given functions. Select the expression that will produce h(x). A. f(x) + f(x) B. f(x) − g(x) C. f(x) + g(x) D. g(x)

− f(x)

1 answer:

Liula [17]3 years ago

3 0

Answer:

here is your answer

Step-by-step explanation:

here is your answer

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A rectangular sand box has a length of 5 1/3 feet and a width of 3 3/4 feet. What is the perimeter in mixed number?

Vadim26 [7]

Answer: 18 1/6 feet

Step-by-step explanation:

From the question, we are informed that the rectangular sand box has a length of 5 1/3 feet and a width of 3 3/4 feet.

The perimeter would be calculated as:

= 2(length + width)

= 2( 5 1/3 + 3 3/4)

= 2( 5 4/12 + 3 9/12)

= 2( 8 13/12)

= 2 (9 1/12)

= 2 × 9 1/12

= 2 × 109/12

= 218/12

= 18 2/12

= 18 1/6 feet

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3 years ago

A rectangle ahs a long side of a length 8.5 cm its perimeter is 24cm work out the length of the shorter side

Phantasy [73]

Answer:

Width (length of shorter side) = 3.5 cm.

Step-by-step explanation:

L = 8.5 cm

perimeter, P = 24 cm

2(L+W) = 24

substitute L = 8.5

2(8.5+W) = 24

8.5 + W = 24/2 = 12

W = 12 - 8.5 = 3.5 cm

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3 years ago

This a 2 part question. F(x) is the graph shown.

Vlada [557]

Suppose f(x) is an even function. The range of g(x) = -3f(2x) is [-9, 3].

Suppose f(x) is an odd function. What is the range of 0.5f(x-3) is [-1.5, 0.5]

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A boy band has released two albums. Their first album sold 5.9×10^5 copies. Their second album sold 1.3×10^6 copies. How many to

prisoha [69]

The band has sold 1,890,000 copies or 1.89 x 10^6

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3 years ago

Read 2 more answers

Determine whether there is a difference between the two data sets that is not apparent from a comparison of the measures of cent

Iteru [2.4K]

Answer:

It seems the question is incomplete as the two data sets implied from the question are not visible.

However, two data sets having identical measures of center have a difference.

Step-by-step explanation:

Let's consider these two data sets:

2, 2, 3, 5, 6, 6 and 1, 1, 1, 1, 1, 19

Both were contrived.

The most reliable among the measures of center is the mean. The mean of each is calculated by summing the data and dividing by the number of elements. In both sets, the mean is 4.

The data in the first set seem to be concentrated around the mean indeed. But for the second data set, one of them, 19, is obviously very far from the others and the mean. We need another measure to describe this: standard deviation.

Its formula is:

$\rho=\sqrt{\dfrac{\sum (x-\overline{x})^2}{n}}$

$x$ represents each data, $\overline{x}$ is the mean and $n$ is the number of items. $x-\overline{x}$ is the deviation from the mean of each data item.

For the first data set, $\rho=\sqrt{6}=2.45$

For the second data set,

$\rho=\sqrt{45}=6.71$

The low value of $\rho$ for the first set indicates that the items are all closer to the mean than for the second set.

Variance is the square of the standard deviation. It could also be used.

7 0

2 years ago