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Nezavi [6.7K]
3 years ago
13

Salvador sold hats during a weekend sporting event. On Saturday, Salvador sold 47 of the total number of hats. On Sunday, he sol

d 14 of the total number of hats. What fraction of the total number of hats was left over
Mathematics
1 answer:
Lilit [14]3 years ago
7 0

Answer:

\frac{x - 61}{x}

Step-by-step explanation:

Let x = total number of hats sold

hat left after sales = x - (47 + 14 ) = x - 61

x - 61 / x

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Clara lends half her collection of formal attires to her sister, Susan. Clara then buys four more attires. If she has 12 attires
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Step-by-step explanation:

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Write the slope of a line parallel to the given line<br> Y=7/4x-2
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Read 2 more answers
You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.
postnew [5]

<em><u>This problem seems to be wrong because no minimum point was found and no point of landing exists</u></em>

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

<u>Derivatives</u>

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

h(x)=2x^2-12x+20

Let's find the first derivative

h'(x)=4x-12

solving h'=0:

4x-12=0

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

2x^2-12x+20=0

Simplifying by 2

x^2-6x+10=0

Completing squares

x^2-6x+9+10-9=0

Factoring and rearranging

(x-3)^2=-1

There is no real value of x to solve the above equation, so the ball will never land.

This problem seems to be wrong because no minimum point was found and no point of landing exists

3 0
3 years ago
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