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Alenkinab [10]
3 years ago
15

Does anyone know how to solve this

Mathematics
1 answer:
madam [21]3 years ago
6 0
Hey I think the answer is letter b if not
I am sorry
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A survey is made to determine the number of households having electric appliances in a certain city. It is found that 75% have r
Mashcka [7]

Answer:

The probability that a household has at least one of these appliances is 0.95

Step-by-step explanation:

Percentage of households having radios P(R) = 75% = 0.75

Percentage of households having electric irons P(I) = 65% = 0.65

Percentage of households having electric toasters P(T) = 55% = 0.55

Percentage of household having iron and radio P(I∩R) = 50% = 0.5

Percentage of household having radios and toasters P(R∩T) = 40% = 0.40

Percentage of household having iron and toasters P(I∩T) = 30% = 0.30

Percentage of household having all three P(I∩R∩T) = 20% = 0.20

Probability of households having at least one of the appliance can be calculated using the rule:

P(at least one of the three) = P(R) +P(I) + P(T) - P(I∩R) - P(R∩T) - P(I∩T) + P(I∩R∩T)

P(at least one of the three)=0.75 + 0.65 + 0.55 - 0.50 - 0.40 - 0.30 + 0.20  P(at least one of the three) = 0.95

The probability that a household has at least one of these appliances is 0.95

3 0
3 years ago
If location a is 87.2 f and location b is 30.3c which is the warmer temperature and by how much
dlinn [17]

Answer: The first place is warmer by .3 degrees Celsius or 32.54 degrees Fahrenheit

Step-by-step explanation:

3 0
3 years ago
Please help do not answer if you don't know it.
iogann1982 [59]
Area parlalelogram=base times height
areatrapizod=(1/2)(base1+base2) times height
areatriangle=1/2 times base times height



1. area=(1/2)(5.9+16.3) times 4.6=51.06
first option

2. area=1/2 times 20.3 times 6.2=62.93
2nd option

3. area=5 and 1/4 times 3=15.75 or 15 and 3/4 or
4th option


4., area=1/2 times 14 times 5.5=38.5
3rd option


5. area= 5.2 times 2.3=11.96
4th option

8 0
3 years ago
Need help with linear approximation
Dmitrij [34]
Consider a function f(x), the linear approximation L(x) of f(x) is given by

L(x)=f(a)+(x-a)f'(a)

Given the quantity: \frac{1}{203}

We approximate the quantity using the function f(x)= \frac{1}{x}, where x = 203.

We choose a = 200, thus the linear approximation is given as follows:

L(203)=f(200)+(203-200)f'(200) \\  \\ = \frac{1}{200} - \frac{3}{200^2} = \frac{200-3}{200^2} = \frac{197}{40,000} =0.004925
5 0
3 years ago
Find the midpoint of the segment between the points (15,−9) and (−2,−18) A. (172,92) B. (13,−27) C. (132,−272) D. (−13,27)
kotegsom [21]

Answer:

from my calculation, the answer is B

5 0
3 years ago
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