2 years ago

Help me, please urgent

Mathematics

2 answers:

mylen [45]2 years ago

3 0

Answer:

2 rays that meet at an end point

Step-by-step explanation:

Natalka [10]2 years ago

3 0

Answer:

Step-by-step explanation:

The endpoint is the little black circle, and the lines and referred to as line segments, because in geometry and angles, lines, never end and will always go on, however, line segments stop after a specific length

You might be interested in

Which statement correctly identifies a local minimum of the graphed function? Over the interval [–3, –2], the local minimum is 0

marta [7]

Answer:

Step-by-step explanation:

As we can see on the graph C is our answer.

4 0

3 years ago

2. Give the degree of x2 - 17x + 2x - 5.00

Evgen [1.6K]

Answer:

Step-by-step explanation:

Degree is the highest power of a term

I hope im right!

5 0

2 years ago

Read 2 more answers

Which answer choices is a run on sentence?

liberstina [14]

A would be the answer John hit the baseball it went over the fence.

7 0

2 years ago

Read 2 more answers

Can someone help me solve this?!

vesna_86 [32]

Answer:

10x+2

Step-by-step explanation:

First we work on the paranthesis. We will times 5 and 2x to get 10x

and then we times 5 and 3/4 to get 3 $\frac{3}{4}$

So now we have 10x+3 $\frac{3}{4}$ -1.75

Next, we subtract 3 $\frac{3}{4}$ -1.75 which is 2

Lastly we look at the equation as a whole!

10x+2

3 0

2 years ago

Find the expression that represents the length of the hypotenuse of a right triangle whose legs measure m^2-n^2 and 2mn

My name is Ann [436]

$\bf c^2=a^2+b^2\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
------\\
a=m^2-n^2\\
b=2mn
\end{cases}\\\\\\ c^2=(m^2-n^2)^2+(\underline{2mn})^2
\\\\\\
c^2=m^4-2m^2n^2+n^4+\underline{2^2m^2n^2}
\\\\\\
c^2=m^4-2m^2n^2+n^4+{4m^2n^2}
\\\\\\
c^2=m^4+2m^2n^2+n^4\impliedby \textit{perfect square trinomial}
\\\\\\
c^2=(m^2+n^2)^2\implies c=\sqrt{(m^2+n^2)^2}\implies c=m^2+n^2$

7 0

3 years ago