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3 years ago

Climate change facts

Physics

1 answer:

yKpoI14uk [10]3 years ago

6 0

Answer:

Climate change exists

Explanation:

some people think it doesn't

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3. The load across a 12-V battery consists of a series combination

Evgesh-ka [11]

Answer:

a. 0.2 A

Explanation:

Given;

voltage of the battery, V = 12 V

three resistance connected in series, R₁ = 15 Ω, R₂ = 21 Ω, R₃ = 24Ω

The equivalent resistance for series connection is calculated as;

Rt = R₁ + R₂ + R₃

Rt = 15Ω + 21Ω + 24Ω

Rt = 60 Ω

Apply Ohm's law to calculate the current n the circuit;

V = IRt

I = V/Rt

I = 12/60

I = 0.2 A

Therefore, the current in the circuit is 0.2 A

7 0

3 years ago

Read each example and identify whether the data are observations or inferences from observations. The fish’s ventral fin measure

drek231 [11]

8.5 cm long just bc we love this

4 0

3 years ago

The outside diameter of the playing area of an optical Blu-ray disc is 11.75 cm, and the inside diameter is 4.50 cm. When viewin

erica [24]

Answer:

The minimum angular speed 57.0 rad/s

Explanation:

In this exercise we must use the relationships between the angular and linear magnitudes, for the speeds we have

v = w r

As they give us that linear velocity is constant, we will calculate the angular velocity for the two radii, external and internal

r1 = 11.75 cm (1 m / 100cm) = 0.1175 m

w1 = v / r1

w1 = 6.70 / 0.1175

w1 = 57.0 rd / s

R2 = 4.50 cm = 0.0450 m

w2 = 6.70 / 0.0450

w2 = 148 rad / s

The minimum angular speed 57.0 rad / s

4 0

3 years ago

A loudspeaker, mounted on a tall pole, is engineered to emit 75% of its sound energy into the forward hemisphere, 25% toward the

Naily [24]

Answer:

"0.049 W" is the correct answer.

Explanation:

According to the given question,

$r = \sqrt{(3.5)^2+(2.5)^2}$

$=\sqrt{8.5}$

$SL=85$

As we know,

⇒ $SL=10 \ log(\frac{I}{I_o} )$

$85=10 \ log(\frac{I}{10^{-12}} )$

$I=3.162\times 1^{-4} \ W/m^2$

Now,

⇒ $P_{front} = I(2\pi r^2)$

$=(3.162\times 10^{-4})(2\pi\times 18.5)$

$=0.0368 \ W$

$=0.75 \ P$

or,

$=0.049 \ W$

7 0

3 years ago

A kangaroo jumps up with an initial velocity of 36 feet persecond from the ground (assume its starting height is 0 feet).Use the

kkurt [141]

Given

Initial velocity:

36 ft/s

Initial height:

0 ft

Vertical motion model:

h(t) = -16t^2 + ut + s

v = initial velocity

s = is the height

Procedure

We are going to use the model provided for the vertical motion.

$\begin{gathered} h(t)=-16t^2+36t+0 \\ h(t)=-16t^2+36t \end{gathered}$

We know that at the maximum height the final velocity is 0.

Then we will use the following expression to calculate the maximum height:

$\begin{gathered} v^2_f=v^2_o-2ah_{\max } \\ 0=v^2_o-2ah_{\max } \\ 2ah_{\max }=v^2_o \\ h_{\max }=\frac{v^2_o}{2a} \\ h_{\max }=\frac{(36ft/s)^2}{2\cdot32ft/s^2} \\ h_{\max }=20.25\text{ ft} \end{gathered}$

Now for time:

$\begin{gathered} 20.25=-16t^2+36t \\ 16t^2-36t+20.25=0 \end{gathered}$

Solving for t,

$\begin{gathered} t_1=2.25 \\ t_2=0 \end{gathered}$

The total time the kangaroo takes in the air is 2.3s.

3 0

1 year ago