<span>2,000,000 nm, algebraic steps below: 2 mm*1 nm 1.0E-6 mm=2,000,000 nm</span>
Answer:
Explanation:
Left block is on surface with higher inclination so it will go down . If T be tension
For motion of block A ,
net force = mgsin60 - (T + mg cos 60 x μ ) , μ is coefficient of friction .
ma = mgsin60 - T - mg cos 60 x .1
10a = 277.13 - T - 16
= 261.13 - T
T = 261.13 - 10a
For motion of block B
T - mg sin30 - mgcos30 x μ = ma
T- 160 - 27.71 = 10 a
261.13 - 10a - 160 - 27.71 = 10a
73.42 = 20a
a = 3.67 ft / s²
common acceleration = 3.67 ft / s²
<span>(symbol K)</span><span> Energy that an object possesses because it is in motion. It is the energy given to an object to set it in motion; it depends on the mass (</span>m) of the object and its velocity (v<span>), according to the equation K = 1/2 </span>mv2<span>. On impact, it is converted into other forms of energy such as heat, sound and light.</span>
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Answer:
Explanation:
We want to find the initial speed of the ball.
To do this, we have to apply the formula for the time of flight of a projectile:
where θ = angle of flight
g = acceleration due to gravity
v0 = initial speed
Therefore, substituting the given values into the formula, we have that:
⇒ 2 × ×0.8910= 9.8 × 4.2
⇒
That is the initial speed of the ball.
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Answer:
1.40625 kg-m^2
Explanation:
Supposing we have to calculate rotational moment of inertia
Given:
Mass of the ball m= 2.50 kg
Length of the rod, L= 0.78 m
The system rotates in a horizontal circle about the other end of the rod
The constant angular velocity of the system, ω= 5010 rev/min
The rotational inertia of system is equal to rotational inertia of the the ball about other end of the rod because the rod is mass-less
=1.40625 kg-m^2
m= mass of the ball and L= length of the ball