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olga_2 [115]
3 years ago
6

The first active volcano observed outside the earth was discovered in 1979 on io, one of the moons of jupiter. suppose a volcano

on another moon is observed to be ejecting material to a height of about 1.52 ✕ 105 m. given that the acceleration of gravity on this moon is 1.91 m/s2 find the initial velocity of the ejected material.
Physics
1 answer:
inna [77]3 years ago
4 0

Gravitation due to the planet's mass is always against the ejected particle velocity. This will result in deceleration of the ejected particle and eventually bring the velocity to zero at the topmost point of the trajectory before pulling it back to the ground.

By the kinematic equation

v^2 - u^2 = 2.a.s

where s is the distance travelled = 1.52 x 10^5 m

a is the acceleration due to gravity = -1.91 m/s^2

v and u are initial and final velocities, so v = 0.

Therefore

u = \sqrt{s.a.s}

u = 761.99 m/s

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In unit-vector notation, what is the net torque about the origin on a flea located at coordinates (-2.0, 4.0 m, -1.0 m) when for
kifflom [539]

Answer:

Torque, \tau=-21i-8j+10k

Explanation:

Given that,

Coordinates, r=(-2i+4j-k)\ m

Force acting on the flea, F=(0i-5j-4k)\ N

Let \tau is the net torque about the origin on a flea. It is given by the following formula :

\tau=r\times F

\tau=(-2i+4j-k)\times (0i-5j-4k)

\tau=\begin{pmatrix}-21&-8&10\end{pmatrix}

\tau=-21i-8j+10k

So, the net torque about the origin on a flea is -21i-8j+10k. Hence, this is the required solution.

6 0
3 years ago
A car drives 215km east and then 45km north. What is the magnitude of the cars displacement? Round you answer to nearest whole n
kifflom [539]

Answer: 219.65\ \text{km}

Explanation:

Given

Car drives 215 km east and then 45 km North

Displacement is East direction is

\Rightarrow \vec{r_1}=215\hat{i}

Now, the displacement from that to 45 km North is given by

\Rightarrow \vec{r_{21}}=45\hat{j}

Net displacement is \vec{r_2}

\Rightarrow \vec{r_2}=\vec{r_1}+\vec{r_{21}}\\\Rightarrow \vec{r_2}=215\hat{i}+45\hat{j}

Magnitude of the displacement is

 \Rightarrow \left | r_{2} \right |=\sqrt{\left ( 215 \right )^2+\left ( 45 \right )^2}\\\Rightarrow  \left | r_{2} \right |=\sqrt{48250}\\\Rightarrow  \left | r_{2} \right |=219.65\ \text{km}

5 0
3 years ago
It has been a hot summer, so when you arrive at a lake, you decide to go for a swim even though it is nighttime. The water is co
ale4655 [162]

Answer: This is because water has a higher Specific Heat Capacity than air.

Explanation:

The specific heat capacity of an object measures how much heat will be required to change its temperature.

Water has a higher specific heat capacity than air, so the temperature of the water will remain fairly constant even though the air surrounding the water is experience temperature changes.

Since air has a lower Specific Heat Capacity than water, heat from the sun will readily heat it up in comparison to water.

6 0
4 years ago
In a race, a runner traveled 12 meters in
Nastasia [14]
     Since it is a race, the runner start from rest, so we can use the Velocity Hourly Equation to describle yours moviment.

S=S_{o}+V_{o}t+ \frac{at^2}{2}  \\ S=\frac{at^2}{2}
 
     Entering the unknowns, we have:

S=\frac{at^2}{2} \\ 12*2=a*4^2 \\ \boxed {a=1.5m/s^2}

Number 2

If you notice any mistake in my english, please let me know, because i am not native.

3 0
3 years ago
Identical isolated conducting spheres 1 and 2 have equal charges and are separated by a distance that is large compared with the
likoan [24]

Answer:

0.375

Explanation:

When the 3rd sphere touches the 1st one, the charge will then be distributed between both of them, then now the 1st sphere has only half of his original charge.

In this moment then

Sphere 1 has a charge = Q/2

Sphere 3 has a charge = Q/2

When the 3rd sphere touches the 2nd sphere again the charge is distributed in a manner that both sphere has the same charge.

How the total charge is

Q = Q/2 + Q = 3/2Q,

When the spheres are separated each one has 3/4Q

Sphere 2 has a charge = 3/4Q

Sphere 3 has a charge = 3/4Q

The electrostatic force that acts on sphere 2 due to sphere 1 is:

F = (kq1q2) / r²

F = (Q/2 * 3Q/4) / r²

F = (Q² * 3) / 8r²

From the question, F = 0.42 = kQ²/r²

Thus, we can say that

F = (0.42 * 3) / 8

F = 0.1575

Thus, the ratio between F/F =

0.1575 / 0.42

Ratio, r = 0.375

4 0
3 years ago
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