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Vaselesa [24]
3 years ago
6

Is one a polygon, two, three?

Mathematics
2 answers:
slega [8]3 years ago
8 0
1 and 2 is but not 3
loris [4]3 years ago
6 0

Answer:

1 and 2 is and 3 is not

Step-by-step explanation:

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404 students were surveyed about their preferences of sports. 126 students like football, 131 students like baseball, and 40 stu
butalik [34]
20 like football
20 like baseball
6 0
3 years ago
Prove that sin20 sin40 sin60 sin80=3/16
xeze [42]
Sin 20° · sin 40° · sin 80° = 1/2 ( cos 20° - cos 60° ) · sin 80° =
= 1/2 ( cos 20° sin 80° - cos 60° sin 80° ) =
= 1/2 ( (sin 100° + sin 60°)/2 - 1/2 sin 80° )=            ( sin 100° = sin 80° )
= 1/2 · ( 1/2 sin 60° ) = 1/4 sin 60° = √3 / 8
sin 60° = √ 3/2
√ 3 / 2 · √ 3 / 8 = 3/16  ( correct )
3 0
3 years ago
it takes Ryan 1/5 of an hour to bike from home to school. His biking speed is 10 MPH. How long will it take Ryan to get to scho
strojnjashka [21]

Answer:

2 hours

Step-by-step explanation:

1/5 * 10

8 0
2 years ago
The plane x + y + 2z = 12 intersects the paraboloid z = x2 + y2 in an ellipse. Find the points on the ellipse that are nearest t
Soloha48 [4]

The distance between a point (x,y,z) and the origin is \sqrt{x^2+y^2+z^2}. But since (\sqrt{f(x)})'=\frac{f'(x)}{2\sqrt{f(x)}}, both f(x) and \sqrt{f(x)} have the same critical points, so we can consider instead the squared distance, x^2+y^2+z^2.

We're looking for the extrema of x^2+y^2+z^2 subject to x+y+2z=12 and z=x^2+y^2. The Lagrangian is

L(x,y,z,\lambda,\mu)=x^2+y^2+z^2+\lambda(x+y+2z-12)+\mu(z-x^2-y^2)

with critical points where the partial derivatives vanish:

L_x=2x+\lambda-2\mu x=0\implies\lambda=2x(\mu-1)

L_y=2y+\lambda-2\mu y=0\implies\lambda=2y(\mu-1)

L_z=2z+2\lambda+\mu=0

L_\lambda=x+y+2z-12=0

L_\mu=z-x^2-y^2=0

From the first two equations, it follows that x=y.

Then in the last two equations,

x+y+2z-12=0\implies x+z=6

z-x^2-y^2=0\implies z=2x^2

\implies x+2x^2=6\implies2x^2+x-6=(2x-3)(x+2)=0\implies x=\dfrac32\text{ or }x=-2

If x=\frac32, then z=6-\frac32=\frac92; if x=-2, then z=8.

So there are two critical points, \left(\frac32,\frac32,\frac92\right) and (-2,-2,8).

Let f(x,y,z)=\sqrt{x^2+y^2+z^2}. We have a minimum distance of f\left(\frac32,\frac32,\frac92\right)=\boxed{\frac{3\sqrt{11}}2} and maximum distance of f(-2,-2,8)=\boxed{6\sqrt2}.

8 0
4 years ago
Which equation describes the same line as y – 6 = –4(x + 1)?
Lorico [155]
I would say c but that is just a guess

5 0
3 years ago
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