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Vaselesa [24]
2 years ago
6

Is one a polygon, two, three?

Mathematics
2 answers:
slega [8]2 years ago
8 0
1 and 2 is but not 3
loris [4]2 years ago
6 0

Answer:

1 and 2 is and 3 is not

Step-by-step explanation:

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Find the equation of a line parallel to y = 3x - 4 that passes through (-2,2).
Grace [21]

Answer:

Slope: 3.

Equation: y = 3x + 8.

Step-by-step explanation:

Lines that are parallel to each other will have the same slopes.

So, the slope of the new line will be 3.

Since we have the slope, and a set of coordinates the line passes through, we can find the equation. So far, we have y = 3x + b. x = -2, y = 2.

2 = 3(-2) + b

3(-2) + b = 2

-6 + b = 2

b = 8

So, the equation of the line will be y = 3x + 8.

Hope this helps!

5 0
3 years ago
A ramp is in the shape of a triangular prism. The ramp and its net are shown below. What is the surface area of the ramp? ​
Over [174]

Answer:

180 ft^2 (squared)

7 0
2 years ago
If your machine takes up 350sq. ft. and you are asked to scale down a drawing onto a 8" x 10" piece of paper what is your percen
Mnenie [13.5K]

Answer:

the scale is 630:1 = 0.16%

80inch^2 of 50400inch^2 however = 0.16%

Step-by-step explanation:

350ft^2 = 50400inches 8 x 10 = 80inches = 50400/80 = 630

50400/9 =5600 we distribute

5600/80 = 7

showing us that 7 x 9 = 63 where 63 x 80 = 5040 1/100th

1 = 630

7x9x 80 = 1/100 of 50400

0.01589 x 7x9x80x 7x9x80 = 80

Proves that every every 10000 the percentage goes down 0.00011%

3 0
3 years ago
Use the whole number product and place value reasoning to place the decimal point in the second product. Explain how you know.
BARSIC [14]
The answer to ypur question is 48.24
5 0
3 years ago
Read 2 more answers
"Find an integer, x, such that 5, 10, and x represent the lengths of the sides of an acute triangle.
Contact [7]
A, b, c - the lengths of the sides of the triangle
and a ≤ b ≤ c
then:
a + b > c and if the triangle is an acute triangle then a² + b² > c².

1^o\\5\leq10\leq x\\\\\left\{\begin{array}{ccc}5+10 \ \textgreater \  x\\5^2+10^2 \ \textgreater \  x^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \  15\\ x^2 \ \textless \  125\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \  15\\ x \ \textless \  \sqrt{125}\approx11.1\end{array}\right\\\\\boxed{x=11}\\\\2^o\\5\leq x\leq10\\\\\left\{\begin{array}{ccc}5+x \ \textgreater \  10\\ 5^2+x^2 \ \textgreater \  10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \  5\\ x^2 \ \textgreater \  75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \  5\\ x \ \textgreater \  \sqrt{75}\approx8.7\end{array}\right\\\boxed{x=9}

3^o\\x\leq5\leq10\\\\\left\{\begin{array}{ccc}x +5 \ \textgreater \  10\\ x^2+5^2 \ \textgreater \  10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x^2 \ \textgreater \ 75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x \ \textgreater \ \sqrt{75}\approx8.7\end{array}\right\\\boxed{x\in\O}\\\\Answer:\boxed{x=9\ or\ x=11}\to your\ answer:\boxed{\boxed{x=11}}
8 0
3 years ago
Read 2 more answers
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