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lys-0071 [83]
3 years ago
15

HELP please please pleaseplease please i will give you 20 points

Mathematics
1 answer:
GenaCL600 [577]3 years ago
3 0

Answer:

surface area =

488cm {}^{2}

Step-by-step explanation:

the given figure is a cuboid,

surface area = 2 ( lb + bh + lh )

( where l is length, b is breadth and h is height )

so,

  • area = 2 ( 16×9 + 9×4 + 16×4 )
  • area = 2 ( 144 + 36 + 64 )
  • area = 2 ( 244 )
  • area = 488

so surface area = 488 cm^2

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To solve -3 = -19 + d/5, what steps would you use?
Pachacha [2.7K]

To solve the expression, the steps are add 19 and multiply by 5

<h3>How to solve the expression</h3>

Given the equation;

-3 = -19 + d/5

First,

Collect like terms

-3+ 19 = d/5

Add the values on the left side

We have

16 = d/5

Cross multiply

16 × 5 = d

We then have

d = 80

Thus, to solve the expression, the steps are add 19 and multiply by 5

Learn  more about algebraic expressions here:

brainly.com/question/4344214

#SPJ1

8 0
2 years ago
Arrange 34,23,42,35,41,19,23 7.3 4.02,5 in ascending order​
Bond [772]

4.02, 5, 7.3, 19, 23, 23, 34, 35, 41, 42

(Numbers are organized in ascending order from smallest to largest)

8 0
4 years ago
Which statement is true?
Nataliya [291]

Answer:

D

Step-by-step explanation:

We can see in the graph f(x) that the x intercept is (1,0).

In the table of g(x), we can see that the x intercept is (-1,0).

Since 1>-1, the x intercept of the graph f(x) is greater than the x intercept of graph g(x).

7 0
3 years ago
Read 2 more answers
Michael spends a half hour adding water to his pool part of the time at a rate of 15 gallons per minute and the rest of the time
NeTakaya

Answer:

24t + 270 gallons

Step-by-step explanation:

Given that :

Addition rate 1 = 15 gallons per minute

Addition rate 2 = 9 gallons per minute

Total time spent adding water = half an hour = 30 minutes = 0.5 hour

Time spent adding water at faster rate = t

Time spent addition water at slower rate = (30 - t)

Total number of water added to the pool :

Amount of water added = addition rate * time

Hence,

Amount of water added at faster rate :

(15 gal / min) * t = 15t gallons

Amount added at slower rate :

(9 gal / min) * (30 - t) = (270 - 9t) gallons

Total amount of water added to the pool:

15t gallons + (270 - 9t)gallons

15t + 270 + 9t

24t + 270 gallons

4 0
3 years ago
3.5 +(1+4 x (6.5 + 1.5)
lutik1710 [3]

Answer:

the answer is 38.5

hope this helps

7 0
4 years ago
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