Answer:X2 = 5
Y2 = 4
ΔX = 4
ΔY = 3
θ = 36.869897645844°
Equation of the line:
y = 0.75x + 0.25
When x=0, y = 0.25
When y=0, x = -0.33333333333333
OR
X2 = -3
Y2 = -2
ΔX = -4
ΔY = -3
θ = 216.86989764584°
Equation of the line:
y = 0.75x + 0.25
When x=0, y = 0.25
When y=0, x = -0.33333333333333
3×(60+7)
(3×30) + (3×7)
90 + 21 = 111
Given:
The area of the rectangular garden is 18z+24 sq ft.
To find the possible dimensions of the garden.
Formula
The area of the rectangular garden is

where,
l be the length of the rectangle
b be the width.
Let us take l and b be the length and width of the given rectangular park respectively.
Now,
According to the problem,

or, 
We can determine that,
l = 6 and b = 3z+4 or vice versa.
Hence,
The possible length and width of the rectangular garden is 6 and (3z+4) respectively.
Answer:
-13x+8
Step-by-step explanation:
add the x's including negatives
4x80=320
Work:
4x8 = 32
(4+4+4+4+4+4+4+4)
Now carry the 0 and you get 320