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OverLord2011 [107]
2 years ago
10

Which I greater? 165 cm or 1.7 meters?

Mathematics
2 answers:
In-s [12.5K]2 years ago
5 0
1.7m..... i think i’m pretty sure
viktelen [127]2 years ago
3 0

165cm in feet is 5.41 feet.

1.7m in feet 5.58 feet

So 1.7m is greater, I hope this helps.

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What’s the slope of the line that passes through 5,10 and 7,12
Marrrta [24]

Slope of the line passes through (5,10) and (7,12) is 1.

Step-by-step explanation:

Given,

The two points are (5,10) and (7,12).

To find the slope passing through the given points.

Formula

The slope of the line passing through (x_{1} ,y_{1}) and (x_{2} ,y_{2}) is \frac{y_{2} -y_{1} }{x_{2} -x_{1} }

Now, putting x_{1} =5,y_{1}=10, x_{2}=7, y_{2} =12 we get,

Slope = \frac{12-10}{7-5} = \frac{2}{2} = 1

Hence,

Slope of the line passes through (5,10) and (7,12) is 1.

7 0
3 years ago
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Find the degree of the polynomial: a^3+3a^2−5a
emmainna [20.7K]

Answer:

The degree of the polynomial is 3

Step-by-step explanation:

Given:

a^3+3a^2-5a

To Find:

The degree of the polynomial= ?

Solution:

The degree of the polynomial   is the value of the greatest exponent of any expression (except the constant ) in the polynomial. To find the degree all that you have to do is find the largest exponent in the polynomial

Here in the given polynomial

a^3+3a^2- 5a

The terms are

a^3

3a^2

5a

The term  a^3 has  the largest exponent of  3

Note:  The degree of the polynomial does not depend  on coefficients of the terms

3 0
3 years ago
What are the types of roots of the equation below?<br> - 81=0
Tju [1.3M]

Option B, that is Two Complex and Two Real which are x + 3, x - 3, x + 3i and x - 3i, are the types of roots of the equation x⁴ - 81 = 0. This can be obtained by finding root of the equation using algebraic identity.    

<h3>What are the types of roots of the equation below?</h3>

Here in the question it is given that,

  • the equation x⁴ - 81 = 0

By using algebraic identity, (a + b)(a - b) = a² - b², we get,  

⇒ x⁴ - 81 = 0                      

⇒ (x² +  9)(x² - 9) = 0

⇒ (x² + 9)(x² - 9) = 0

  1. (x² -  9) = (x² - 3²) = (x - 3)(x + 3) [using algebraic identity, (a + b)(a - b) = a² - b²]
  2. x² + 9 = 0 ⇒ x² = -9 ⇒ x = √-9 ⇒ x= √-1√9 ⇒x = ± 3i

⇒ (x² + 9) = (x - 3i)(x + 3i)

Now the equation becomes,

[(x - 3)(x + 3)][(x - 3i)(x + 3i)] = 0

Therefore x + 3, x - 3, x + 3i and x - 3i are the roots of the equation

To check whether the roots are correct multiply the roots with each other,

⇒ [(x - 3)(x + 3)][(x - 3i)(x + 3i)] = 0

⇒ [x² - 3x + 3x - 9][x² - 3xi + 3xi - 9i²] = 0

⇒ (x² +0x - 9)(x² +0xi - 9(- 1)) = 0

⇒ (x² - 9)(x² + 9) = 0

⇒ x⁴ - 9x² + 9x² - 81 = 0

⇒ x⁴ - 81 = 0

Hence Option B, that is Two Complex and Two Real which are x + 3, x - 3, x + 3i and x - 3i, are the types of roots of the equation x⁴ - 81 = 0.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: What are the types of roots of the equation below?

x⁴ - 81 = 0

A) Four Complex

B) Two Complex and Two Real

C) Four Real

Learn more about roots of equation here:

brainly.com/question/26926523

#SPJ9

5 0
1 year ago
PLZ HELP ME I BEG U 50 pints
yarga [219]

Answer:

1496.79 mm squared

Step-by-step explanation:

Have a good day :)

3 0
3 years ago
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Find the value of x. please help me with my test
Lady bird [3.3K]

Step-by-step explanation:

180 -angled triangle,

180-56 = 124

124/2 = 62 (each corner of the right triangle)

then find the corner below

the rectangle has right angles on the right side

x = 90-62

= 28

8 0
2 years ago
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